{ "data": { "question": { "questionId": "2406", "questionFrontendId": "2325", "categoryTitle": "Algorithms", "boundTopicId": 1632815, "title": "Decode the Message", "titleSlug": "decode-the-message", "content": "

You are given the strings key and message, which represent a cipher key and a secret message, respectively. The steps to decode message are as follows:

\n\n
    \n\t
  1. Use the first appearance of all 26 lowercase English letters in key as the order of the substitution table.
  2. \n\t
  3. Align the substitution table with the regular English alphabet.
  4. \n\t
  5. Each letter in message is then substituted using the table.
  6. \n\t
  7. Spaces ' ' are transformed to themselves.
  8. \n
\n\n\n\n

Return the decoded message.

\n\n

 

\n

Example 1:

\n\"\"\n
\nInput: key = "the quick brown fox jumps over the lazy dog", message = "vkbs bs t suepuv"\nOutput: "this is a secret"\nExplanation: The diagram above shows the substitution table.\nIt is obtained by taking the first appearance of each letter in "the quick brown fox jumps over the lazy dog".\n
\n\n

Example 2:

\n\"\"\n
\nInput: key = "eljuxhpwnyrdgtqkviszcfmabo", message = "zwx hnfx lqantp mnoeius ycgk vcnjrdb"\nOutput: "the five boxing wizards jump quickly"\nExplanation: The diagram above shows the substitution table.\nIt is obtained by taking the first appearance of each letter in "eljuxhpwnyrdgtqkviszcfmabo".\n
\n\n

 

\n

Constraints:

\n\n\n", "translatedTitle": "解密消息", "translatedContent": "

给你字符串 keymessage ,分别表示一个加密密钥和一段加密消息。解密 message 的步骤如下:

\n\n
    \n\t
  1. 使用 key 中 26 个英文小写字母第一次出现的顺序作为替换表中的字母 顺序
  2. \n\t
  3. 将替换表与普通英文字母表对齐,形成对照表。
  4. \n\t
  5. 按照对照表 替换 message 中的每个字母。
  6. \n\t
  7. 空格 ' ' 保持不变。
  8. \n
\n\n\n\n

返回解密后的消息。

\n\n

 

\n\n

示例 1:

\n\n

\"\"

\n\n
\n输入:key = \"the quick brown fox jumps over the lazy dog\", message = \"vkbs bs t suepuv\"\n输出:\"this is a secret\"\n解释:对照表如上图所示。\n提取 \"the quick brown fox jumps over the lazy dog\" 中每个字母的首次出现可以得到替换表。\n
\n\n

示例 2:

\n\n

\"\"

\n\n
\n输入:key = \"eljuxhpwnyrdgtqkviszcfmabo\", message = \"zwx hnfx lqantp mnoeius ycgk vcnjrdb\"\n输出:\"the five boxing wizards jump quickly\"\n解释:对照表如上图所示。\n提取 \"eljuxhpwnyrdgtqkviszcfmabo\" 中每个字母的首次出现可以得到替换表。\n
\n\n

 

\n\n

提示:

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string? string?)\n )", "__typename": "CodeSnippetNode" }, { "lang": "Erlang", "langSlug": "erlang", "code": "-spec decode_message(Key :: unicode:unicode_binary(), Message :: unicode:unicode_binary()) -> unicode:unicode_binary().\ndecode_message(Key, Message) ->\n .", "__typename": "CodeSnippetNode" }, { "lang": "Elixir", "langSlug": "elixir", "code": "defmodule Solution do\n @spec decode_message(key :: String.t, message :: String.t) :: String.t\n def decode_message(key, message) do\n \n end\nend", "__typename": "CodeSnippetNode" }, { "lang": "Cangjie", "langSlug": "cangjie", "code": "class Solution {\n func decodeMessage(key: String, message: String): String {\n\n }\n}", "__typename": "CodeSnippetNode" } ], "stats": "{\"totalAccepted\": \"47.7K\", \"totalSubmission\": \"56.5K\", \"totalAcceptedRaw\": 47721, \"totalSubmissionRaw\": 56451, \"acRate\": \"84.5%\"}", "hints": [ "Iterate through the characters in the key to construct a mapping to the English alphabet.", "Make sure to check that the current character is not already in the mapping (only the first appearance is considered).", "Map the characters in the message according to the constructed mapping." ], "solution": null, "status": null, "sampleTestCase": "\"the quick brown fox jumps over the lazy dog\"\n\"vkbs bs t suepuv\"", "metaData": "{\n \"name\": \"decodeMessage\",\n \"params\": [\n {\n \"name\": \"key\",\n \"type\": \"string\"\n },\n {\n \"type\": \"string\",\n \"name\": \"message\"\n }\n ],\n \"return\": {\n \"type\": \"string\"\n }\n}", "judgerAvailable": true, "judgeType": "large", "mysqlSchemas": [], "enableRunCode": true, "envInfo": "{\"cpp\":[\"C++\",\"

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