{ "data": { "question": { "questionId": "1294", "questionFrontendId": "2080", "categoryTitle": "Algorithms", "boundTopicId": 1110237, "title": "Range Frequency Queries", "titleSlug": "range-frequency-queries", "content": "
Design a data structure to find the frequency of a given value in a given subarray.
\n\nThe frequency of a value in a subarray is the number of occurrences of that value in the subarray.
\n\nImplement the RangeFreqQuery
class:
RangeFreqQuery(int[] arr)
Constructs an instance of the class with the given 0-indexed integer array arr
.int query(int left, int right, int value)
Returns the frequency of value
in the subarray arr[left...right]
.A subarray is a contiguous sequence of elements within an array. arr[left...right]
denotes the subarray that contains the elements of nums
between indices left
and right
(inclusive).
\n
Example 1:
\n\n\nInput\n["RangeFreqQuery", "query", "query"]\n[[[12, 33, 4, 56, 22, 2, 34, 33, 22, 12, 34, 56]], [1, 2, 4], [0, 11, 33]]\nOutput\n[null, 1, 2]\n\nExplanation\nRangeFreqQuery rangeFreqQuery = new RangeFreqQuery([12, 33, 4, 56, 22, 2, 34, 33, 22, 12, 34, 56]);\nrangeFreqQuery.query(1, 2, 4); // return 1. The value 4 occurs 1 time in the subarray [33, 4]\nrangeFreqQuery.query(0, 11, 33); // return 2. The value 33 occurs 2 times in the whole array.\n\n\n
\n
Constraints:
\n\n1 <= arr.length <= 105
1 <= arr[i], value <= 104
0 <= left <= right < arr.length
105
calls will be made to query
请你设计一个数据结构,它能求出给定子数组内一个给定值的 频率 。
\n\n子数组中一个值的 频率 指的是这个子数组中这个值的出现次数。
\n\n请你实现 RangeFreqQuery
类:
RangeFreqQuery(int[] arr)
用下标从 0 开始的整数数组 arr
构造一个类的实例。int query(int left, int right, int value)
返回子数组 arr[left...right]
中 value
的 频率 。一个 子数组 指的是数组中一段连续的元素。arr[left...right]
指的是 nums
中包含下标 left
和 right
在内 的中间一段连续元素。
\n\n
示例 1:
\n\n输入:\n[\"RangeFreqQuery\", \"query\", \"query\"]\n[[[12, 33, 4, 56, 22, 2, 34, 33, 22, 12, 34, 56]], [1, 2, 4], [0, 11, 33]]\n输出:\n[null, 1, 2]\n\n解释:\nRangeFreqQuery rangeFreqQuery = new RangeFreqQuery([12, 33, 4, 56, 22, 2, 34, 33, 22, 12, 34, 56]);\nrangeFreqQuery.query(1, 2, 4); // 返回 1 。4 在子数组 [33, 4] 中出现 1 次。\nrangeFreqQuery.query(0, 11, 33); // 返回 2 。33 在整个子数组中出现 2 次。\n\n\n
\n\n
提示:
\n\n1 <= arr.length <= 105
1 <= arr[i], value <= 104
0 <= left <= right < arr.length
query
不超过 105
次。\\u7248\\u672c\\uff1a \\u7f16\\u8bd1\\u65f6\\uff0c\\u5c06\\u4f1a\\u91c7\\u7528 \\u4e3a\\u4e86\\u4f7f\\u7528\\u65b9\\u4fbf\\uff0c\\u5927\\u90e8\\u5206\\u6807\\u51c6\\u5e93\\u7684\\u5934\\u6587\\u4ef6\\u5df2\\u7ecf\\u88ab\\u81ea\\u52a8\\u5bfc\\u5165\\u3002<\\/p>\"],\"java\":[\"Java\",\" \\u7248\\u672c\\uff1a \\u4e3a\\u4e86\\u65b9\\u4fbf\\u8d77\\u89c1\\uff0c\\u5927\\u90e8\\u5206\\u6807\\u51c6\\u5e93\\u7684\\u5934\\u6587\\u4ef6\\u5df2\\u88ab\\u5bfc\\u5165\\u3002<\\/p>\\r\\n\\r\\n \\u5305\\u542b Pair \\u7c7b: https:\\/\\/docs.oracle.com\\/javase\\/8\\/javafx\\/api\\/javafx\\/util\\/Pair.html <\\/p>\"],\"python\":[\"Python\",\" \\u7248\\u672c\\uff1a \\u4e3a\\u4e86\\u65b9\\u4fbf\\u8d77\\u89c1\\uff0c\\u5927\\u90e8\\u5206\\u5e38\\u7528\\u5e93\\u5df2\\u7ecf\\u88ab\\u81ea\\u52a8 \\u5bfc\\u5165\\uff0c\\u5982\\uff1aarray<\\/a>, bisect<\\/a>, 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