{ "data": { "question": { "questionId": "1072", "questionFrontendId": "1019", "categoryTitle": "Algorithms", "boundTopicId": 3325, "title": "Next Greater Node In Linked List", "titleSlug": "next-greater-node-in-linked-list", "content": "
You are given the head
of a linked list with n
nodes.
For each node in the list, find the value of the next greater node. That is, for each node, find the value of the first node that is next to it and has a strictly larger value than it.
\n\nReturn an integer array answer
where answer[i]
is the value of the next greater node of the ith
node (1-indexed). If the ith
node does not have a next greater node, set answer[i] = 0
.
\n
Example 1:
\n\n\nInput: head = [2,1,5]\nOutput: [5,5,0]\n\n\n
Example 2:
\n\n\nInput: head = [2,7,4,3,5]\nOutput: [7,0,5,5,0]\n\n\n
\n
Constraints:
\n\nn
.1 <= n <= 104
1 <= Node.val <= 109
给定一个长度为 n
的链表 head
对于列表中的每个节点,查找下一个 更大节点 的值。也就是说,对于每个节点,找到它旁边的第一个节点的值,这个节点的值 严格大于 它的值。
\n\n返回一个整数数组 answer
,其中 answer[i]
是第 i
个节点( 从1开始 )的下一个更大的节点的值。如果第 i
个节点没有下一个更大的节点,设置 answer[i] = 0
。
\n\n
示例 1:
\n\n\n\n\n输入:head = [2,1,5]\n输出:[5,5,0]\n\n\n
示例 2:
\n\n\n\n\n输入:head = [2,7,4,3,5]\n输出:[7,0,5,5,0]\n\n\n
\n\n
提示:
\n\nn
1 <= n <= 104
1 <= Node.val <= 109
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