{ "data": { "question": { "questionId": "1989", "questionFrontendId": "1879", "categoryTitle": "Algorithms", "boundTopicId": 796301, "title": "Minimum XOR Sum of Two Arrays", "titleSlug": "minimum-xor-sum-of-two-arrays", "content": "

You are given two integer arrays nums1 and nums2 of length n.

\n\n

The XOR sum of the two integer arrays is (nums1[0] XOR nums2[0]) + (nums1[1] XOR nums2[1]) + ... + (nums1[n - 1] XOR nums2[n - 1]) (0-indexed).

\n\n\n\n

Rearrange the elements of nums2 such that the resulting XOR sum is minimized.

\n\n

Return the XOR sum after the rearrangement.

\n\n

 

\n

Example 1:

\n\n
\nInput: nums1 = [1,2], nums2 = [2,3]\nOutput: 2\nExplanation: Rearrange nums2 so that it becomes [3,2].\nThe XOR sum is (1 XOR 3) + (2 XOR 2) = 2 + 0 = 2.
\n\n

Example 2:

\n\n
\nInput: nums1 = [1,0,3], nums2 = [5,3,4]\nOutput: 8\nExplanation: Rearrange nums2 so that it becomes [5,4,3]. \nThe XOR sum is (1 XOR 5) + (0 XOR 4) + (3 XOR 3) = 4 + 4 + 0 = 8.\n
\n\n

 

\n

Constraints:

\n\n\n", "translatedTitle": "两个数组最小的异或值之和", "translatedContent": "

给你两个整数数组 nums1 和 nums2 ，它们长度都为 n 。

\n\n

两个数组的 异或值之和 为 (nums1[0] XOR nums2[0]) + (nums1[1] XOR nums2[1]) + ... + (nums1[n - 1] XOR nums2[n - 1]) （下标从 0 开始）。

\n\n\n\n

请你将 nums2 中的元素重新排列，使得 异或值之和 最小 。

\n\n

请你返回重新排列之后的 异或值之和 。

\n\n

 

\n\n

示例 1：

\n\n
输入：nums1 = [1,2], nums2 = [2,3]\n输出：2\n解释：将 nums2 重新排列得到 [3,2] 。\n异或值之和为 (1 XOR 3) + (2 XOR 2) = 2 + 0 = 2 。
\n\n

示例 2：

\n\n
输入：nums1 = [1,0,3], nums2 = [5,3,4]\n输出：8\n解释：将 nums2 重新排列得到 [5,4,3] 。\n异或值之和为 (1 XOR 5) + (0 XOR 4) + (3 XOR 3) = 4 + 4 + 0 = 8 。\n
\n\n

 

\n\n

提示：

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