{ "data": { "question": { "questionId": "3327", "questionFrontendId": "3086", "categoryTitle": "Algorithms", "boundTopicId": 2689643, "title": "Minimum Moves to Pick K Ones", "titleSlug": "minimum-moves-to-pick-k-ones", "content": "
You are given a binary array nums
of length n
, a positive integer k
and a non-negative integer maxChanges
.
Alice plays a game, where the goal is for Alice to pick up k
ones from nums
using the minimum number of moves. When the game starts, Alice picks up any index aliceIndex
in the range [0, n - 1]
and stands there. If nums[aliceIndex] == 1
, Alice picks up the one and nums[aliceIndex]
becomes 0
(this does not count as a move). After this, Alice can make any number of moves (including zero) where in each move Alice must perform exactly one of the following actions:
j != aliceIndex
such that nums[j] == 0
and set nums[j] = 1
. This action can be performed at most maxChanges
times.x
and y
(|x - y| == 1
) such that nums[x] == 1
, nums[y] == 0
, then swap their values (set nums[y] = 1
and nums[x] = 0
). If y == aliceIndex
, Alice picks up the one after this move and nums[y]
becomes 0
.Return the minimum number of moves required by Alice to pick exactly k
ones.
\n
Example 1:
\n\nInput: nums = [1,1,0,0,0,1,1,0,0,1], k = 3, maxChanges = 1
\n\nOutput: 3
\n\nExplanation: Alice can pick up 3
ones in 3
moves, if Alice performs the following actions in each move when standing at aliceIndex == 1
:
nums[1]
becomes 0
. nums
becomes [1,1,1,0,0,1,1,0,0,1]
.j == 2
and perform an action of the first type. nums
becomes [1,0,1,0,0,1,1,0,0,1]
x == 2
and y == 1
, and perform an action of the second type. nums
becomes [1,1,0,0,0,1,1,0,0,1]
. As y == aliceIndex
, Alice picks up the one and nums
becomes [1,0,0,0,0,1,1,0,0,1]
.x == 0
and y == 1
, and perform an action of the second type. nums
becomes [0,1,0,0,0,1,1,0,0,1]
. As y == aliceIndex
, Alice picks up the one and nums
becomes [0,0,0,0,0,1,1,0,0,1]
.Note that it may be possible for Alice to pick up 3
ones using some other sequence of 3
moves.
Example 2:
\n\nInput: nums = [0,0,0,0], k = 2, maxChanges = 3
\n\nOutput: 4
\n\nExplanation: Alice can pick up 2
ones in 4
moves, if Alice performs the following actions in each move when standing at aliceIndex == 0
:
j == 1
and perform an action of the first type. nums
becomes [0,1,0,0]
.x == 1
and y == 0
, and perform an action of the second type. nums
becomes [1,0,0,0]
. As y == aliceIndex
, Alice picks up the one and nums
becomes [0,0,0,0]
.j == 1
again and perform an action of the first type. nums
becomes [0,1,0,0]
.x == 1
and y == 0
again, and perform an action of the second type. nums
becomes [1,0,0,0]
. As y == aliceIndex
, Alice picks up the one and nums
becomes [0,0,0,0]
.\n
Constraints:
\n\n2 <= n <= 105
0 <= nums[i] <= 1
1 <= k <= 105
0 <= maxChanges <= 105
maxChanges + sum(nums) >= k
给你一个下标从 0 开始的二进制数组 nums
,其长度为 n
;另给你一个 正整数 k
以及一个 非负整数 maxChanges
。
Alice 在玩一个游戏,游戏的目标是让 Alice 使用 最少 数量的 行动 次数从 nums
中拾起 k
个 1 。游戏开始时,Alice 可以选择数组 [0, n - 1]
范围内的任何索引 aliceIndex
站立。如果 nums[aliceIndex] == 1
,Alice 会拾起一个 1 ,并且 nums[aliceIndex]
变成0
(这 不算 作一次行动)。之后,Alice 可以执行 任意数量 的 行动(包括零次),在每次行动中 Alice 必须 恰好 执行以下动作之一:
j != aliceIndex
且满足 nums[j] == 0
,然后将 nums[j]
设置为 1
。这个动作最多可以执行 maxChanges
次。x
和 y
(|x - y| == 1
)且满足 nums[x] == 1
, nums[y] == 0
,然后交换它们的值(将 nums[y] = 1
和 nums[x] = 0
)。如果 y == aliceIndex
,在这次行动后 Alice 拾起一个 1 ,并且 nums[y]
变成 0
。返回 Alice 拾起 恰好 k
个 1 所需的 最少 行动次数。
\n\n
示例 1:
\n\n输入:nums = [1,1,0,0,0,1,1,0,0,1], k = 3, maxChanges = 1
\n\n输出:3
\n\n解释:如果游戏开始时 Alice 在 aliceIndex == 1
的位置上,按照以下步骤执行每个动作,他可以利用 3
次行动拾取 3
个 1 :
nums[1]
变成了 0
。此时 nums
变为 [1,1,1,0,0,1,1,0,0,1]
。j == 2
并执行第一种类型的动作。nums
变为 [1,0,1,0,0,1,1,0,0,1]
x == 2
和 y == 1
,并执行第二种类型的动作。nums
变为 [1,1,0,0,0,1,1,0,0,1]
。由于 y == aliceIndex
,Alice 拾取了一个 1 ,nums
变为 [1,0,0,0,0,1,1,0,0,1]
。x == 0
和 y == 1
,并执行第二种类型的动作。nums
变为 [0,1,0,0,0,1,1,0,0,1]
。由于 y == aliceIndex
,Alice 拾取了一个 1 ,nums
变为 [0,0,0,0,0,1,1,0,0,1]
。请注意,Alice 也可能执行其他的 3
次行动序列达成拾取 3
个 1 。
示例 2:
\n\n输入:nums = [0,0,0,0], k = 2, maxChanges = 3
\n\n输出:4
\n\n解释:如果游戏开始时 Alice 在 aliceIndex == 0
的位置上,按照以下步骤执行每个动作,他可以利用 4
次行动拾取 2
个 1 :
j == 1
并执行第一种类型的动作。nums
变为 [0,1,0,0]
。x == 1
和 y == 0
,并执行第二种类型的动作。nums
变为 [1,0,0,0]
。由于 y == aliceIndex
,Alice 拾起了一个 1 ,nums
变为 [0,0,0,0]
。j == 1
并执行第一种类型的动作。nums
变为 [0,1,0,0]
。x == 1
和 y == 0
,并执行第二种类型的动作。nums
变为 [1,0,0,0]
。由于y == aliceIndex
,Alice 拾起了一个 1 ,nums
变为 [0,0,0,0]
。\n\n
提示:
\n\n2 <= n <= 105
0 <= nums[i] <= 1
1 <= k <= 105
0 <= maxChanges <= 105
maxChanges + sum(nums) >= k
2
moves. Hence except for the immediate neighbors of the index where we move all the ones, we should try to use change operations.",
"For some subset of ones, it is always better to move the ones to the median position.",
"We only need to be concerned with the indices where nums[i] == 1
."
],
"solution": null,
"status": null,
"sampleTestCase": "[1,1,0,0,0,1,1,0,0,1]\n3\n1",
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