You are given two 0-indexed integer arrays nums1 and nums2, each of length n, and a 1-indexed 2D array queries where queries[i] = [xi, yi].
For the ith query, find the maximum value of nums1[j] + nums2[j] among all indices j (0 <= j < n), where nums1[j] >= xi and nums2[j] >= yi, or -1 if there is no j satisfying the constraints.
Return an array answer where answer[i] is the answer to the ith query.
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Example 1:
\n\n\nInput: nums1 = [4,3,1,2], nums2 = [2,4,9,5], queries = [[4,1],[1,3],[2,5]]\nOutput: [6,10,7]\nExplanation: \nFor the 1st query\n\nxi = 4andyi = 1, we can select indexj = 0sincenums1[j] >= 4andnums2[j] >= 1. The sumnums1[j] + nums2[j]is 6, and we can show that 6 is the maximum we can obtain.\n\nFor the 2nd queryxi = 1andyi = 3, we can select indexj = 2sincenums1[j] >= 1andnums2[j] >= 3. The sumnums1[j] + nums2[j]is 10, and we can show that 10 is the maximum we can obtain. \n\nFor the 3rd queryxi = 2andyi = 5, we can select indexj = 3sincenums1[j] >= 2andnums2[j] >= 5. The sumnums1[j] + nums2[j]is 7, and we can show that 7 is the maximum we can obtain.\n\nTherefore, we return[6,10,7].\n
Example 2:
\n\n\nInput: nums1 = [3,2,5], nums2 = [2,3,4], queries = [[4,4],[3,2],[1,1]]\nOutput: [9,9,9]\nExplanation: For this example, we can use index j = 2 for all the queries since it satisfies the constraints for each query.\n\n\nExample 3:
\n\n\nInput: nums1 = [2,1], nums2 = [2,3], queries = [[3,3]]\nOutput: [-1]\nExplanation: There is one query in this example with\n\nxi= 3 andyi= 3. For every index, j, either nums1[j] <xior nums2[j] <yi. Hence, there is no solution. \n
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Constraints:
\n\nnums1.length == nums2.length n == nums1.length 1 <= n <= 1051 <= nums1[i], nums2[i] <= 109 1 <= queries.length <= 105queries[i].length == 2xi == queries[i][1]yi == queries[i][2]1 <= xi, yi <= 109给你两个长度为 n 、下标从 0 开始的整数数组 nums1 和 nums2 ，另给你一个下标从 1 开始的二维数组 queries ，其中 queries[i] = [xi, yi] 。
对于第 i 个查询，在所有满足 nums1[j] >= xi 且 nums2[j] >= yi 的下标 j (0 <= j < n) 中，找出 nums1[j] + nums2[j] 的 最大值 ，如果不存在满足条件的 j 则返回 -1 。
返回数组 answer ，其中 answer[i] 是第 i 个查询的答案。
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示例 1：
\n\n输入：nums1 = [4,3,1,2], nums2 = [2,4,9,5], queries = [[4,1],[1,3],[2,5]]\n输出：[6,10,7]\n解释：\n对于第 1 个查询：\n\nxi = 4且yi = 1，可以选择下标j = 0，此时nums1[j] >= 4且nums2[j] >= 1。nums1[j] + nums2[j]等于 6 ，可以证明 6 是可以获得的最大值。\n对于第 2 个查询：xi = 1且yi = 3，可以选择下标j = 2，此时nums1[j] >= 1且nums2[j] >= 3。nums1[j] + nums2[j]等于 10 ，可以证明 10 是可以获得的最大值。\n对于第 3 个查询：xi = 2且yi = 5，可以选择下标j = 3，此时nums1[j] >= 2且nums2[j] >= 5。nums1[j] + nums2[j]等于 7 ，可以证明 7 是可以获得的最大值。\n因此，我们返回[6,10,7]。\n
示例 2：
\n\n输入：nums1 = [3,2,5], nums2 = [2,3,4], queries = [[4,4],[3,2],[1,1]]\n输出：[9,9,9]\n解释：对于这个示例，我们可以选择下标 j = 2 ，该下标可以满足每个查询的限制。\n\n\n示例 3：
\n\n输入：nums1 = [2,1], nums2 = [2,3], queries = [[3,3]]\n输出：[-1]\n解释：示例中的查询\n\nxi= 3 且yi= 3 。对于每个下标 j ，都只满足 nums1[j] <xi或者 nums2[j] <yi。因此，不存在答案。 \n
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提示：
\n\nnums1.length == nums2.length n == nums1.length 1 <= n <= 1051 <= nums1[i], nums2[i] <= 109 1 <= queries.length <= 105queries[i].length == 2xi == queries[i][1]yi == queries[i][2]1 <= xi, yi <= 109\\u7248\\u672c\\uff1a \\u7f16\\u8bd1\\u65f6\\uff0c\\u5c06\\u4f1a\\u91c7\\u7528 \\u4e3a\\u4e86\\u4f7f\\u7528\\u65b9\\u4fbf\\uff0c\\u5927\\u90e8\\u5206\\u6807\\u51c6\\u5e93\\u7684\\u5934\\u6587\\u4ef6\\u5df2\\u7ecf\\u88ab\\u81ea\\u52a8\\u5bfc\\u5165\\u3002<\\/p>\"],\"java\":[\"Java\",\" \\u7248\\u672c\\uff1a \\u4e3a\\u4e86\\u65b9\\u4fbf\\u8d77\\u89c1\\uff0c\\u5927\\u90e8\\u5206\\u6807\\u51c6\\u5e93\\u7684\\u5934\\u6587\\u4ef6\\u5df2\\u88ab\\u5bfc\\u5165\\u3002<\\/p>\\r\\n\\r\\n \\u5305\\u542b Pair \\u7c7b: https:\\/\\/docs.oracle.com\\/javase\\/8\\/javafx\\/api\\/javafx\\/util\\/Pair.html <\\/p>\"],\"python\":[\"Python\",\" \\u7248\\u672c\\uff1a \\u4e3a\\u4e86\\u65b9\\u4fbf\\u8d77\\u89c1\\uff0c\\u5927\\u90e8\\u5206\\u5e38\\u7528\\u5e93\\u5df2\\u7ecf\\u88ab\\u81ea\\u52a8 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