{ "data": { "question": { "questionId": "3316", "questionFrontendId": "3098", "categoryTitle": "Algorithms", "boundTopicId": 2713798, "title": "Find the Sum of Subsequence Powers", "titleSlug": "find-the-sum-of-subsequence-powers", "content": "
You are given an integer array nums
of length n
, and a positive integer k
.
The power of a subsequence is defined as the minimum absolute difference between any two elements in the subsequence.
\n\nReturn the sum of powers of all subsequences of nums
which have length equal to k
.
Since the answer may be large, return it modulo 109 + 7
.
\n
Example 1:
\n\nInput: nums = [1,2,3,4], k = 3
\n\nOutput: 4
\n\nExplanation:
\n\nThere are 4 subsequences in nums
which have length 3: [1,2,3]
, [1,3,4]
, [1,2,4]
, and [2,3,4]
. The sum of powers is |2 - 3| + |3 - 4| + |2 - 1| + |3 - 4| = 4
.
Example 2:
\n\nInput: nums = [2,2], k = 2
\n\nOutput: 0
\n\nExplanation:
\n\nThe only subsequence in nums
which has length 2 is [2,2]
. The sum of powers is |2 - 2| = 0
.
Example 3:
\n\nInput: nums = [4,3,-1], k = 2
\n\nOutput: 10
\n\nExplanation:
\n\nThere are 3 subsequences in nums
which have length 2: [4,3]
, [4,-1]
, and [3,-1]
. The sum of powers is |4 - 3| + |4 - (-1)| + |3 - (-1)| = 10
.
\n
Constraints:
\n\n2 <= n == nums.length <= 50
-108 <= nums[i] <= 108
2 <= k <= n
给你一个长度为 n
的整数数组 nums
和一个 正 整数 k
。
一个子序列的 能量 定义为子序列中 任意 两个元素的差值绝对值的 最小值 。
\n\n请你返回 nums
中长度 等于 k
的 所有 子序列的 能量和 。
由于答案可能会很大,将答案对 109 + 7
取余 后返回。
\n\n
示例 1:
\n\n输入:nums = [1,2,3,4], k = 3
\n\n输出:4
\n\n解释:
\n\nnums
中总共有 4 个长度为 3 的子序列:[1,2,3]
,[1,3,4]
,[1,2,4]
和 [2,3,4]
。能量和为 |2 - 3| + |3 - 4| + |2 - 1| + |3 - 4| = 4
。
示例 2:
\n\n输入:nums = [2,2], k = 2
\n\n输出:0
\n\n解释:
\n\nnums
中唯一一个长度为 2 的子序列是 [2,2]
。能量和为 |2 - 2| = 0
。
示例 3:
\n\n输入:nums = [4,3,-1], k = 2
\n\n输出:10
\n\n解释:
\n\nnums
总共有 3 个长度为 2 的子序列:[4,3]
,[4,-1]
和 [3,-1]
。能量和为 |4 - 3| + |4 - (-1)| + |3 - (-1)| = 10
。
\n\n
提示:
\n\n2 <= n == nums.length <= 50
-108 <= nums[i] <= 108
2 <= k <= n
nums
.",
"There are at most n2
distinct differences.",
"For a particular difference d
, let dp[len][i][j]
be the number of subsequences of length len
in the subarray nums[0..i]
where the last element picked was at index j
.",
"For each index, we can check if it can be picked if nums[i] - nums[j] <= d
."
],
"solution": null,
"status": null,
"sampleTestCase": "[1,2,3,4]\n3",
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