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            "categoryTitle": "Algorithms",
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            "title": "Distribute Elements Into Two Arrays II",
            "titleSlug": "distribute-elements-into-two-arrays-ii",
            "content": "<p>You are given a <strong>1-indexed</strong> array of integers <code>nums</code> of length <code>n</code>.</p>\n\n<p>We define a function <code>greaterCount</code> such that <code>greaterCount(arr, val)</code> returns the number of elements in <code>arr</code> that are <strong>strictly greater</strong> than <code>val</code>.</p>\n\n<p>You need to distribute all the elements of <code>nums</code> between two arrays <code>arr1</code> and <code>arr2</code> using <code>n</code> operations. In the first operation, append <code>nums[1]</code> to <code>arr1</code>. In the second operation, append <code>nums[2]</code> to <code>arr2</code>. Afterwards, in the <code>i<sup>th</sup></code> operation:</p>\n\n<ul>\n\t<li>If <code>greaterCount(arr1, nums[i]) &gt; greaterCount(arr2, nums[i])</code>, append <code>nums[i]</code> to <code>arr1</code>.</li>\n\t<li>If <code>greaterCount(arr1, nums[i]) &lt; greaterCount(arr2, nums[i])</code>, append <code>nums[i]</code> to <code>arr2</code>.</li>\n\t<li>If <code>greaterCount(arr1, nums[i]) == greaterCount(arr2, nums[i])</code>, append <code>nums[i]</code> to the array with a <strong>lesser</strong> number of elements.</li>\n\t<li>If there is still a tie, append <code>nums[i]</code> to <code>arr1</code>.</li>\n</ul>\n\n<p>The array <code>result</code> is formed by concatenating the arrays <code>arr1</code> and <code>arr2</code>. For example, if <code>arr1 == [1,2,3]</code> and <code>arr2 == [4,5,6]</code>, then <code>result = [1,2,3,4,5,6]</code>.</p>\n\n<p>Return <em>the integer array</em> <code>result</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [2,1,3,3]\n<strong>Output:</strong> [2,3,1,3]\n<strong>Explanation:</strong> After the first 2 operations, arr1 = [2] and arr2 = [1].\nIn the 3<sup>rd</sup> operation, the number of elements greater than 3 is zero in both arrays. Also, the lengths are equal, hence, append nums[3] to arr1.\nIn the 4<sup>th</sup> operation, the number of elements greater than 3 is zero in both arrays. As the length of arr2 is lesser, hence, append nums[4] to arr2.\nAfter 4 operations, arr1 = [2,3] and arr2 = [1,3].\nHence, the array result formed by concatenation is [2,3,1,3].\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [5,14,3,1,2]\n<strong>Output:</strong> [5,3,1,2,14]\n<strong>Explanation:</strong> After the first 2 operations, arr1 = [5] and arr2 = [14].\nIn the 3<sup>rd</sup> operation, the number of elements greater than 3 is one in both arrays. Also, the lengths are equal, hence, append nums[3] to arr1.\nIn the 4<sup>th</sup> operation, the number of elements greater than 1 is greater in arr1 than arr2 (2 &gt; 1). Hence, append nums[4] to arr1.\nIn the 5<sup>th</sup> operation, the number of elements greater than 2 is greater in arr1 than arr2 (2 &gt; 1). Hence, append nums[5] to arr1.\nAfter 5 operations, arr1 = [5,3,1,2] and arr2 = [14].\nHence, the array result formed by concatenation is [5,3,1,2,14].\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [3,3,3,3]\n<strong>Output:</strong> [3,3,3,3]\n<strong>Explanation:</strong> At the end of 4 operations, arr1 = [3,3] and arr2 = [3,3].\nHence, the array result formed by concatenation is [3,3,3,3].\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>3 &lt;= n &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= 10<sup>9</sup></code></li>\n</ul>\n",
            "translatedTitle": "将元素分配到两个数组中 II",
            "translatedContent": "<p>给你一个下标从 <strong>1</strong> 开始、长度为 <code>n</code> 的整数数组 <code>nums</code> 。</p>\n\n<p>现定义函数 <code>greaterCount</code> ，使得 <code>greaterCount(arr, val)</code> 返回数组 <code>arr</code> 中<strong> 严格大于</strong> <code>val</code> 的元素数量。</p>\n\n<p>你需要使用 <code>n</code> 次操作，将 <code>nums</code> 的所有元素分配到两个数组 <code>arr1</code> 和 <code>arr2</code> 中。在第一次操作中，将 <code>nums[1]</code> 追加到 <code>arr1</code> 。在第二次操作中，将 <code>nums[2]</code> 追加到 <code>arr2</code> 。之后，在第 <code>i</code> 次操作中：</p>\n\n<ul>\n\t<li>如果 <code>greaterCount(arr1, nums[i]) &gt; greaterCount(arr2, nums[i])</code> ，将 <code>nums[i]</code> 追加到 <code>arr1</code> 。</li>\n\t<li>如果 <code>greaterCount(arr1, nums[i]) &lt; greaterCount(arr2, nums[i])</code> ，将 <code>nums[i]</code> 追加到 <code>arr2</code> 。</li>\n\t<li>如果 <code>greaterCount(arr1, nums[i]) == greaterCount(arr2, nums[i])</code> ，将 <code>nums[i]</code> 追加到元素数量较少的数组中。</li>\n\t<li>如果仍然相等，那么将 <code>nums[i]</code> 追加到 <code>arr1</code> 。</li>\n</ul>\n\n<p>连接数组 <code>arr1</code> 和 <code>arr2</code> 形成数组 <code>result</code> 。例如，如果 <code>arr1 == [1,2,3]</code> 且 <code>arr2 == [4,5,6]</code> ，那么 <code>result = [1,2,3,4,5,6]</code> 。</p>\n\n<p>返回整数数组 <code>result</code> 。</p>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [2,1,3,3]\n<strong>输出：</strong>[2,3,1,3]\n<strong>解释：</strong>在前两次操作后，arr1 = [2] ，arr2 = [1] 。\n在第 3 次操作中，两个数组中大于 3 的元素数量都是零，并且长度相等，因此，将 nums[3] 追加到 arr1 。\n在第 4 次操作中，两个数组中大于 3 的元素数量都是零，但 arr2 的长度较小，因此，将 nums[4] 追加到 arr2 。\n在 4 次操作后，arr1 = [2,3] ，arr2 = [1,3] 。\n因此，连接形成的数组 result 是 [2,3,1,3] 。\n</pre>\n\n<p><strong class=\"example\">示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [5,14,3,1,2]\n<strong>输出：</strong>[5,3,1,2,14]\n<strong>解释：</strong>在前两次操作后，arr1 = [5] ，arr2 = [14] 。\n在第 3 次操作中，两个数组中大于 3 的元素数量都是一，并且长度相等，因此，将 nums[3] 追加到 arr1 。\n在第 4 次操作中，arr1 中大于 1 的元素数量大于 arr2 中的数量（2 &gt; 1），因此，将 nums[4] 追加到 arr1 。\n在第 5 次操作中，arr1 中大于 2 的元素数量大于 arr2 中的数量（2 &gt; 1），因此，将 nums[5] 追加到 arr1 。\n在 5 次操作后，arr1 = [5,3,1,2] ，arr2 = [14] 。\n因此，连接形成的数组 result 是 [5,3,1,2,14] 。\n</pre>\n\n<p><strong class=\"example\">示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [3,3,3,3]\n<strong>输出：</strong>[3,3,3,3]\n<strong>解释：</strong>在 4 次操作后，arr1 = [3,3] ，arr2 = [3,3] 。\n因此，连接形成的数组 result 是 [3,3,3,3] 。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>3 &lt;= n &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= 10<sup>9</sup></code></li>\n</ul>\n",
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target=\\\"_blank\\\">Apple\\u653e\\u51fa\\u7684\\u6700\\u65b0\\u7248Swift<\\/a>\\u3002\\u5982\\u679c\\u60a8\\u53d1\\u73b0Swift\\u4e0d\\u662f\\u6700\\u65b0\\u7248\\u7684\\uff0c\\u8bf7\\u8054\\u7cfb\\u6211\\u4eec\\uff01\\u6211\\u4eec\\u5c06\\u5c3d\\u5feb\\u66f4\\u65b0\\u3002<\\/p>\"],\"golang\":[\"Go\",\"<p>\\u7248\\u672c\\uff1a<code>Go 1.21<\\/code><\\/p>\\r\\n\\r\\n<p>\\u652f\\u6301 <a href=\\\"https:\\/\\/pkg.go.dev\\/github.com\\/emirpasic\\/gods@v1.18.1\\\" target=\\\"_blank\\\">https:\\/\\/pkg.go.dev\\/github.com\\/emirpasic\\/gods@v1.18.1<\\/a> \\u548c <a href=\\\"https:\\/\\/pkg.go.dev\\/github.com\\/emirpasic\\/gods\\/v2@v2.0.0-alpha\\\" target=\\\"_blank\\\">https:\\/\\/pkg.go.dev\\/github.com\\/emirpasic\\/gods\\/v2@v2.0.0-alpha<\\/a> \\u7b2c\\u4e09\\u65b9\\u5e93\\u3002<\\/p>\"],\"python3\":[\"Python3\",\"<p>\\u7248\\u672c\\uff1a<code>Python 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