{ "data": { "question": { "questionId": "1572", "questionFrontendId": "1476", "categoryTitle": "Algorithms", "boundTopicId": 283331, "title": "Subrectangle Queries", "titleSlug": "subrectangle-queries", "content": "
Implement the class SubrectangleQueries
which receives a rows x cols
rectangle as a matrix of integers in the constructor and supports two methods:
1. updateSubrectangle(int row1, int col1, int row2, int col2, int newValue)
newValue
in the subrectangle whose upper left coordinate is (row1,col1)
and bottom right coordinate is (row2,col2)
.2. getValue(int row, int col)
(row,col)
from the rectangle.\n
Example 1:
\n\n\nInput\n["SubrectangleQueries","getValue","updateSubrectangle","getValue","getValue","updateSubrectangle","getValue","getValue"]\n[[[[1,2,1],[4,3,4],[3,2,1],[1,1,1]]],[0,2],[0,0,3,2,5],[0,2],[3,1],[3,0,3,2,10],[3,1],[0,2]]\nOutput\n[null,1,null,5,5,null,10,5]\nExplanation\nSubrectangleQueries subrectangleQueries = new SubrectangleQueries([[1,2,1],[4,3,4],[3,2,1],[1,1,1]]); \n// The initial rectangle (4x3) looks like:\n// 1 2 1\n// 4 3 4\n// 3 2 1\n// 1 1 1\nsubrectangleQueries.getValue(0, 2); // return 1\nsubrectangleQueries.updateSubrectangle(0, 0, 3, 2, 5);\n// After this update the rectangle looks like:\n// 5 5 5\n// 5 5 5\n// 5 5 5\n// 5 5 5 \nsubrectangleQueries.getValue(0, 2); // return 5\nsubrectangleQueries.getValue(3, 1); // return 5\nsubrectangleQueries.updateSubrectangle(3, 0, 3, 2, 10);\n// After this update the rectangle looks like:\n// 5 5 5\n// 5 5 5\n// 5 5 5\n// 10 10 10 \nsubrectangleQueries.getValue(3, 1); // return 10\nsubrectangleQueries.getValue(0, 2); // return 5\n\n\n
Example 2:
\n\n\nInput\n["SubrectangleQueries","getValue","updateSubrectangle","getValue","getValue","updateSubrectangle","getValue"]\n[[[[1,1,1],[2,2,2],[3,3,3]]],[0,0],[0,0,2,2,100],[0,0],[2,2],[1,1,2,2,20],[2,2]]\nOutput\n[null,1,null,100,100,null,20]\nExplanation\nSubrectangleQueries subrectangleQueries = new SubrectangleQueries([[1,1,1],[2,2,2],[3,3,3]]);\nsubrectangleQueries.getValue(0, 0); // return 1\nsubrectangleQueries.updateSubrectangle(0, 0, 2, 2, 100);\nsubrectangleQueries.getValue(0, 0); // return 100\nsubrectangleQueries.getValue(2, 2); // return 100\nsubrectangleQueries.updateSubrectangle(1, 1, 2, 2, 20);\nsubrectangleQueries.getValue(2, 2); // return 20\n\n\n
\n
Constraints:
\n\n500
operations considering both methods: updateSubrectangle
and getValue
.1 <= rows, cols <= 100
rows == rectangle.length
cols == rectangle[i].length
0 <= row1 <= row2 < rows
0 <= col1 <= col2 < cols
1 <= newValue, rectangle[i][j] <= 10^9
0 <= row < rows
0 <= col < cols
请你实现一个类 SubrectangleQueries
,它的构造函数的参数是一个 rows x cols
的矩形(这里用整数矩阵表示),并支持以下两种操作:
1. updateSubrectangle(int row1, int col1, int row2, int col2, int newValue)
newValue
更新以 (row1,col1)
为左上角且以 (row2,col2)
为右下角的子矩形。2. getValue(int row, int col)
(row,col)
的当前值。\n\n
示例 1:
\n\n输入:\n["SubrectangleQueries","getValue","updateSubrectangle","getValue","getValue","updateSubrectangle","getValue","getValue"]\n[[[[1,2,1],[4,3,4],[3,2,1],[1,1,1]]],[0,2],[0,0,3,2,5],[0,2],[3,1],[3,0,3,2,10],[3,1],[0,2]]\n输出:\n[null,1,null,5,5,null,10,5]\n解释:\nSubrectangleQueries subrectangleQueries = new SubrectangleQueries([[1,2,1],[4,3,4],[3,2,1],[1,1,1]]); \n// 初始的 (4x3) 矩形如下:\n// 1 2 1\n// 4 3 4\n// 3 2 1\n// 1 1 1\nsubrectangleQueries.getValue(0, 2); // 返回 1\nsubrectangleQueries.updateSubrectangle(0, 0, 3, 2, 5);\n// 此次更新后矩形变为:\n// 5 5 5\n// 5 5 5\n// 5 5 5\n// 5 5 5 \nsubrectangleQueries.getValue(0, 2); // 返回 5\nsubrectangleQueries.getValue(3, 1); // 返回 5\nsubrectangleQueries.updateSubrectangle(3, 0, 3, 2, 10);\n// 此次更新后矩形变为:\n// 5 5 5\n// 5 5 5\n// 5 5 5\n// 10 10 10 \nsubrectangleQueries.getValue(3, 1); // 返回 10\nsubrectangleQueries.getValue(0, 2); // 返回 5\n\n\n
示例 2:
\n\n输入:\n["SubrectangleQueries","getValue","updateSubrectangle","getValue","getValue","updateSubrectangle","getValue"]\n[[[[1,1,1],[2,2,2],[3,3,3]]],[0,0],[0,0,2,2,100],[0,0],[2,2],[1,1,2,2,20],[2,2]]\n输出:\n[null,1,null,100,100,null,20]\n解释:\nSubrectangleQueries subrectangleQueries = new SubrectangleQueries([[1,1,1],[2,2,2],[3,3,3]]);\nsubrectangleQueries.getValue(0, 0); // 返回 1\nsubrectangleQueries.updateSubrectangle(0, 0, 2, 2, 100);\nsubrectangleQueries.getValue(0, 0); // 返回 100\nsubrectangleQueries.getValue(2, 2); // 返回 100\nsubrectangleQueries.updateSubrectangle(1, 1, 2, 2, 20);\nsubrectangleQueries.getValue(2, 2); // 返回 20\n\n\n
\n\n
提示:
\n\n500
次updateSubrectangle
和 getValue
操作。1 <= rows, cols <= 100
rows == rectangle.length
cols == rectangle[i].length
0 <= row1 <= row2 < rows
0 <= col1 <= col2 < cols
1 <= newValue, rectangle[i][j] <= 10^9
0 <= row < rows
0 <= col < cols
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