{ "data": { "question": { "questionId": "3493", "questionFrontendId": "3228", "categoryTitle": "Algorithms", "boundTopicId": 2849196, "title": "Maximum Number of Operations to Move Ones to the End", "titleSlug": "maximum-number-of-operations-to-move-ones-to-the-end", "content": "
You are given a binary string s
.
You can perform the following operation on the string any number of times:
\n\ni
from the string where i + 1 < s.length
such that s[i] == '1'
and s[i + 1] == '0'
.s[i]
to the right until it reaches the end of the string or another '1'
. For example, for s = "010010"
, if we choose i = 1
, the resulting string will be s = "000110"
.Return the maximum number of operations that you can perform.
\n\n\n
Example 1:
\n\nInput: s = "1001101"
\n\nOutput: 4
\n\nExplanation:
\n\nWe can perform the following operations:
\n\ni = 0
. The resulting string is s = "0011101"
.i = 4
. The resulting string is s = "0011011"
.i = 3
. The resulting string is s = "0010111"
.i = 2
. The resulting string is s = "0001111"
.Example 2:
\n\nInput: s = "00111"
\n\nOutput: 0
\n\n
Constraints:
\n\n1 <= s.length <= 105
s[i]
is either '0'
or '1'
.给你一个 二进制字符串 s
。
你可以对这个字符串执行 任意次 下述操作:
\n\ni
( i + 1 < s.length
),该下标满足 s[i] == '1'
且 s[i + 1] == '0'
。s[i]
向 右移 直到它到达字符串的末端或另一个 '1'
。例如,对于 s = \"010010\"
,如果我们选择 i = 1
,结果字符串将会是 s = \"000110\"
。返回你能执行的 最大 操作次数。
\n\n\n\n
示例 1:
\n\n输入: s = \"1001101\"
\n\n输出: 4
\n\n解释:
\n\n可以执行以下操作:
\n\ni = 0
。结果字符串为 s = \"0011101\"
。i = 4
。结果字符串为 s = \"0011011\"
。i = 3
。结果字符串为 s = \"0010111\"
。i = 2
。结果字符串为 s = \"0001111\"
。示例 2:
\n\n输入: s = \"00111\"
\n\n输出: 0
\n\n\n
提示:
\n\n1 <= s.length <= 105
s[i]
为 '0'
或 '1'
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