You are given a 0-indexed integer array nums. Rearrange the values of nums according to the following rules:
nums in non-increasing order.\n\n\tnums = [4,1,2,3] before this step, it becomes [4,3,2,1] after. The values at odd indices 1 and 3 are sorted in non-increasing order.nums in non-decreasing order.\n\tnums = [4,1,2,3] before this step, it becomes [2,1,4,3] after. The values at even indices 0 and 2 are sorted in non-decreasing order.Return the array formed after rearranging the values of nums.
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Example 1:
\n\n\nInput: nums = [4,1,2,3]\nOutput: [2,3,4,1]\nExplanation: \nFirst, we sort the values present at odd indices (1 and 3) in non-increasing order.\nSo, nums changes from [4,1,2,3] to [4,3,2,1].\nNext, we sort the values present at even indices (0 and 2) in non-decreasing order.\nSo, nums changes from [4,1,2,3] to [2,3,4,1].\nThus, the array formed after rearranging the values is [2,3,4,1].\n\n\n
Example 2:
\n\n\nInput: nums = [2,1]\nOutput: [2,1]\nExplanation: \nSince there is exactly one odd index and one even index, no rearrangement of values takes place.\nThe resultant array formed is [2,1], which is the same as the initial array. \n\n\n
\n
Constraints:
\n\n1 <= nums.length <= 1001 <= nums[i] <= 100Compiled with clang 11 using the latest C++ 20 standard.
Your code is compiled with level two optimization (-O2). AddressSanitizer is also enabled to help detect out-of-bounds and use-after-free bugs.
Most standard library headers are already included automatically for your convenience.
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