You are given an integer array nums where the ith bag contains nums[i] balls. You are also given an integer maxOperations.
You can perform the following operation at most maxOperations times:
5 balls can become two new bags of 1 and 4 balls, or two new bags of 2 and 3 balls.Your penalty is the maximum number of balls in a bag. You want to minimize your penalty after the operations.
\n\nReturn the minimum possible penalty after performing the operations.
\n\n\n
Example 1:
\n\n\nInput: nums = [9], maxOperations = 2\nOutput: 3\nExplanation: \n- Divide the bag with 9 balls into two bags of sizes 6 and 3. [9] -> [6,3].\n- Divide the bag with 6 balls into two bags of sizes 3 and 3. [6,3] -> [3,3,3].\nThe bag with the most number of balls has 3 balls, so your penalty is 3 and you should return 3.\n\n\n
Example 2:
\n\n\nInput: nums = [2,4,8,2], maxOperations = 4\nOutput: 2\nExplanation:\n- Divide the bag with 8 balls into two bags of sizes 4 and 4. [2,4,8,2] -> [2,4,4,4,2].\n- Divide the bag with 4 balls into two bags of sizes 2 and 2. [2,4,4,4,2] -> [2,2,2,4,4,2].\n- Divide the bag with 4 balls into two bags of sizes 2 and 2. [2,2,2,4,4,2] -> [2,2,2,2,2,4,2].\n- Divide the bag with 4 balls into two bags of sizes 2 and 2. [2,2,2,2,2,4,2] -> [2,2,2,2,2,2,2,2].\nThe bag with the most number of balls has 2 balls, so your penalty is 2, and you should return 2.\n\n\n
\n
Constraints:
\n\n1 <= nums.length <= 1051 <= maxOperations, nums[i] <= 109Compiled with clang 11 using the latest C++ 20 standard.
Your code is compiled with level two optimization (-O2). AddressSanitizer is also enabled to help detect out-of-bounds and use-after-free bugs.
Most standard library headers are already included automatically for your convenience.
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