You are given an integer k and an integer x.
Consider s is the 1-indexed binary representation of an integer num. The price of a number num is the number of i's such that i % x == 0 and s[i] is a set bit.
Return the greatest integer num such that the sum of prices of all numbers from 1 to num is less than or equal to k.
Note:
\n\n1.s == 11100, s[4] == 1 and s[2] == 0.\n
Example 1:
\n\n\nInput: k = 9, x = 1\nOutput: 6\nExplanation: The numbers 1, 2, 3, 4, 5, and 6 can be written in binary representation as "1", "10", "11", "100", "101", and "110" respectively.\nSince x is equal to 1, the price of each number is the number of its set bits.\nThe number of set bits in these numbers is 9. So the sum of the prices of the first 6 numbers is 9.\nSo the answer is 6.\n\n
Example 2:
\n\n\nInput: k = 7, x = 2\nOutput: 9\nExplanation: Since x is equal to 2, we should just check eventh bits.\nThe second bit of binary representation of numbers 2 and 3 is a set bit. So the sum of their prices is 2.\nThe second bit of binary representation of numbers 6 and 7 is a set bit. So the sum of their prices is 2.\nThe fourth bit of binary representation of numbers 8 and 9 is a set bit but their second bit is not. So the sum of their prices is 2.\nNumbers 1, 4, and 5 don't have set bits in their eventh bits in their binary representation. So the sum of their prices is 0.\nThe second and the fourth bit of the binary representation of the number 10 are a set bit. So its price is 2.\nThe sum of the prices of the first 9 numbers is 6.\nBecause the sum of the prices of the first 10 numbers is 8, the answer is 9.\n\n
\n
Constraints:
\n\n1 <= k <= 10151 <= x <= 8ith position. Then calculate the sum of them."
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