You are given a string s consisting of only lowercase English letters. In one operation, you can:
s, ori letters of s if the first i letters of s are equal to the following i letters in s, for any i in the range 1 <= i <= s.length / 2.For example, if s = "ababc", then in one operation, you could delete the first two letters of s to get "abc", since the first two letters of s and the following two letters of s are both equal to "ab".
Return the maximum number of operations needed to delete all of s.
\n
Example 1:
\n\n\nInput: s = "abcabcdabc"\nOutput: 2\nExplanation:\n- Delete the first 3 letters ("abc") since the next 3 letters are equal. Now, s = "abcdabc".\n- Delete all the letters.\nWe used 2 operations so return 2. It can be proven that 2 is the maximum number of operations needed.\nNote that in the second operation we cannot delete "abc" again because the next occurrence of "abc" does not happen in the next 3 letters.\n\n\nExample 2:
\n\n\nInput: s = "aaabaab"\nOutput: 4\nExplanation:\n- Delete the first letter ("a") since the next letter is equal. Now, s = "aabaab".\n- Delete the first 3 letters ("aab") since the next 3 letters are equal. Now, s = "aab".\n- Delete the first letter ("a") since the next letter is equal. Now, s = "ab".\n- Delete all the letters.\nWe used 4 operations so return 4. It can be proven that 4 is the maximum number of operations needed.\n\n\nExample 3:
\n\n\nInput: s = "aaaaa"\nOutput: 5\nExplanation: In each operation, we can delete the first letter of s.\n\n\n
\n
Constraints:
\n\n1 <= s.length <= 4000s consists only of lowercase English letters.Compiled with clang 11 using the latest C++ 20 standard.
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