{ "data": { "question": { "questionId": "3251", "questionFrontendId": "3000", "boundTopicId": null, "title": "Maximum Area of Longest Diagonal Rectangle", "titleSlug": "maximum-area-of-longest-diagonal-rectangle", "content": "

You are given a 2D 0-indexed integer array dimensions.

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For all indices i, 0 <= i < dimensions.length, dimensions[i][0] represents the length and dimensions[i][1] represents the width of the rectangle i.

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Return the area of the rectangle having the longest diagonal. If there are multiple rectangles with the longest diagonal, return the area of the rectangle having the maximum area.

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Example 1:

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\nInput: dimensions = [[9,3],[8,6]]\nOutput: 48\nExplanation: \nFor index = 0, length = 9 and width = 3. Diagonal length = sqrt(9 * 9 + 3 * 3) = sqrt(90) ≈ 9.487.\nFor index = 1, length = 8 and width = 6. Diagonal length = sqrt(8 * 8 + 6 * 6) = sqrt(100) = 10.\nSo, the rectangle at index 1 has a greater diagonal length therefore we return area = 8 * 6 = 48.\n
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Example 2:

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\nInput: dimensions = [[3,4],[4,3]]\nOutput: 12\nExplanation: Length of diagonal is the same for both which is 5, so maximum area = 12.\n
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Constraints:

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