The frequency of an element is the number of times it occurs in an array.
\n\nYou are given an integer array nums and an integer k. In one operation, you can choose an index of nums and increment the element at that index by 1.
Return the maximum possible frequency of an element after performing at most k operations.
\n
Example 1:
\n\n\nInput: nums = [1,2,4], k = 5\nOutput: 3\nExplanation: Increment the first element three times and the second element two times to make nums = [4,4,4].\n4 has a frequency of 3.\n\n
Example 2:
\n\n\nInput: nums = [1,4,8,13], k = 5\nOutput: 2\nExplanation: There are multiple optimal solutions:\n- Increment the first element three times to make nums = [4,4,8,13]. 4 has a frequency of 2.\n- Increment the second element four times to make nums = [1,8,8,13]. 8 has a frequency of 2.\n- Increment the third element five times to make nums = [1,4,13,13]. 13 has a frequency of 2.\n\n\n
Example 3:
\n\n\nInput: nums = [3,9,6], k = 2\nOutput: 1\n\n\n
\n
Constraints:
\n\n1 <= nums.length <= 1051 <= nums[i] <= 1051 <= k <= 105Compiled with clang 11 using the latest C++ 20 standard.
Your code is compiled with level two optimization (-O2). AddressSanitizer is also enabled to help detect out-of-bounds and use-after-free bugs.
Most standard library headers are already included automatically for your convenience.
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