You and a gang of thieves are planning on robbing a bank. You are given a 0-indexed integer array security, where security[i] is the number of guards on duty on the ith day. The days are numbered starting from 0. You are also given an integer time.
The ith day is a good day to rob the bank if:
time days before and after the ith day,time days before i are non-increasing, andtime days after i are non-decreasing.More formally, this means day i is a good day to rob the bank if and only if security[i - time] >= security[i - time + 1] >= ... >= security[i] <= ... <= security[i + time - 1] <= security[i + time].
Return a list of all days (0-indexed) that are good days to rob the bank. The order that the days are returned in does not matter.
\n\n\n
Example 1:
\n\n\nInput: security = [5,3,3,3,5,6,2], time = 2\nOutput: [2,3]\nExplanation:\nOn day 2, we have security[0] >= security[1] >= security[2] <= security[3] <= security[4].\nOn day 3, we have security[1] >= security[2] >= security[3] <= security[4] <= security[5].\nNo other days satisfy this condition, so days 2 and 3 are the only good days to rob the bank.\n\n\n
Example 2:
\n\n\nInput: security = [1,1,1,1,1], time = 0\nOutput: [0,1,2,3,4]\nExplanation:\nSince time equals 0, every day is a good day to rob the bank, so return every day.\n\n\n
Example 3:
\n\n\nInput: security = [1,2,3,4,5,6], time = 2\nOutput: []\nExplanation:\nNo day has 2 days before it that have a non-increasing number of guards.\nThus, no day is a good day to rob the bank, so return an empty list.\n\n\n
\n
Constraints:
\n\n1 <= security.length <= 1050 <= security[i], time <= 105Compiled with clang 11 using the latest C++ 20 standard.
Your code is compiled with level two optimization (-O2). AddressSanitizer is also enabled to help detect out-of-bounds and use-after-free bugs.
Most standard library headers are already included automatically for your convenience.
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