You are given two 0-indexed binary strings s1 and s2, both of length n, and a positive integer x.
You can perform any of the following operations on the string s1 any number of times:
i and j, and flip both s1[i] and s1[j]. The cost of this operation is x.i such that i < n - 1 and flip both s1[i] and s1[i + 1]. The cost of this operation is 1.Return the minimum cost needed to make the strings s1 and s2 equal, or return -1 if it is impossible.
Note that flipping a character means changing it from 0 to 1 or vice-versa.
\n
Example 1:
\n\n\nInput: s1 = "1100011000", s2 = "0101001010", x = 2\nOutput: 4\nExplanation: We can do the following operations:\n- Choose i = 3 and apply the second operation. The resulting string is s1 = "1101111000".\n- Choose i = 4 and apply the second operation. The resulting string is s1 = "1101001000".\n- Choose i = 0 and j = 8 and apply the first operation. The resulting string is s1 = "0101001010" = s2.\nThe total cost is 1 + 1 + 2 = 4. It can be shown that it is the minimum cost possible.\n\n\n
Example 2:
\n\n\nInput: s1 = "10110", s2 = "00011", x = 4\nOutput: -1\nExplanation: It is not possible to make the two strings equal.\n\n\n
\n
Constraints:
\n\nn == s1.length == s2.length1 <= n, x <= 500s1 and s2 consist only of the characters '0' and '1'.s1 and s2 into a list, and work only with this list.",
"Try to use dynamic programming on this list to solve the problem. What will be the states and transitions of this dp?"
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