You have a certain number of processors, each having 4 cores. The number of tasks to be executed is four times the number of processors. Each task must be assigned to a unique core, and each core can only be used once.
\n\nYou are given an array processorTime representing the time each processor becomes available and an array tasks representing how long each task takes to complete. Return the minimum time needed to complete all tasks.
\n
Example 1:
\n\nInput: processorTime = [8,10], tasks = [2,2,3,1,8,7,4,5]
\n\nOutput: 16
\n\nExplanation:
\n\nAssign the tasks at indices 4, 5, 6, 7 to the first processor which becomes available at time = 8, and the tasks at indices 0, 1, 2, 3 to the second processor which becomes available at time = 10.
The time taken by the first processor to finish the execution of all tasks is max(8 + 8, 8 + 7, 8 + 4, 8 + 5) = 16.
The time taken by the second processor to finish the execution of all tasks is max(10 + 2, 10 + 2, 10 + 3, 10 + 1) = 13.
Example 2:
\n\nInput: processorTime = [10,20], tasks = [2,3,1,2,5,8,4,3]
\n\nOutput: 23
\n\nExplanation:
\n\nAssign the tasks at indices 1, 4, 5, 6 to the first processor and the others to the second processor.
\n\nThe time taken by the first processor to finish the execution of all tasks is max(10 + 3, 10 + 5, 10 + 8, 10 + 4) = 18.
The time taken by the second processor to finish the execution of all tasks is max(20 + 2, 20 + 1, 20 + 2, 20 + 3) = 23.
\n
Constraints:
\n\n1 <= n == processorTime.length <= 250001 <= tasks.length <= 1050 <= processorTime[i] <= 1091 <= tasks[i] <= 109tasks.length == 4 * n你有 n 颗处理器，每颗处理器都有 4 个核心。现有 n * 4 个待执行任务，每个核心只执行 一次 任务。
给你一个下标从 0 开始的整数数组 processorTime ，表示每颗处理器最早空闲时间。另给你一个下标从 0 开始的整数数组 tasks ，表示执行每个任务所需的时间。返回所有任务都执行完毕需要的 最小时间 。
注意：每个核心独立执行任务。
\n\n\n\n
示例 1：
\n\n\n输入：processorTime = [8,10], tasks = [2,2,3,1,8,7,4,5]\n输出：16\n解释：\n最优的方案是将下标为 4, 5, 6, 7 的任务分配给第一颗处理器（最早空闲时间 time = 8），下标为 0, 1, 2, 3 的任务分配给第二颗处理器（最早空闲时间 time = 10）。 \n第一颗处理器执行完所有任务需要花费的时间 = max(8 + 8, 8 + 7, 8 + 4, 8 + 5) = 16 。\n第二颗处理器执行完所有任务需要花费的时间 = max(10 + 2, 10 + 2, 10 + 3, 10 + 1) = 13 。\n因此，可以证明执行完所有任务需要花费的最小时间是 16 。\n\n
示例 2：
\n\n\n输入：processorTime = [10,20], tasks = [2,3,1,2,5,8,4,3]\n输出：23\n解释：\n最优的方案是将下标为 1, 4, 5, 6 的任务分配给第一颗处理器（最早空闲时间 time = 10），下标为 0, 2, 3, 7 的任务分配给第二颗处理器（最早空闲时间 time = 20）。 \n第一颗处理器执行完所有任务需要花费的时间 = max(10 + 3, 10 + 5, 10 + 8, 10 + 4) = 18 。 \n第二颗处理器执行完所有任务需要花费的时间 = max(20 + 2, 20 + 1, 20 + 2, 20 + 3) = 23 。 \n因此，可以证明执行完所有任务需要花费的最小时间是 23 。\n\n\n
\n\n
提示：
\n\n1 <= n == processorTime.length <= 250001 <= tasks.length <= 1050 <= processorTime[i] <= 1091 <= tasks[i] <= 109tasks.length == 4 * nprocessTime[i] + tasks[j] (when matched) is the answer."
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