{ "data": { "question": { "questionId": "3344", "questionFrontendId": "3102", "categoryTitle": "Algorithms", "boundTopicId": 2673010, "title": "Minimize Manhattan Distances", "titleSlug": "minimize-manhattan-distances", "content": "

You are given an array points representing integer coordinates of some points on a 2D plane, where points[i] = [xi, yi].

\n\n

The distance between two points is defined as their Manhattan distance.

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Return the minimum possible value for maximum distance between any two points by removing exactly one point.

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\n

Example 1:

\n\n
\n

Input: points = [[3,10],[5,15],[10,2],[4,4]]

\n\n

Output: 12

\n\n

Explanation:

\n\n

The maximum distance after removing each point is the following:

\n\n\n\n

12 is the minimum possible maximum distance between any two points after removing exactly one point.

\n
\n\n

Example 2:

\n\n
\n

Input: points = [[1,1],[1,1],[1,1]]

\n\n

Output: 0

\n\n

Explanation:

\n\n

Removing any of the points results in the maximum distance between any two points of 0.

\n
\n\n

 

\n

Constraints:

\n\n\n", "translatedTitle": "最小化曼哈顿距离", "translatedContent": "

给你一个下标从 0 开始的数组 points ,它表示二维平面上一些点的整数坐标,其中 points[i] = [xi, yi]

\n\n

两点之间的距离定义为它们的曼哈顿距离

\n\n

请你恰好移除一个点,返回移除后任意两点之间的 最大 距离可能的 最小 值。

\n\n

 

\n\n

示例 1:

\n\n
\n输入:points = [[3,10],[5,15],[10,2],[4,4]]\n输出:12\n解释:移除每个点后的最大距离如下所示:\n- 移除第 0 个点后,最大距离在点 (5, 15) 和 (10, 2) 之间,为 |5 - 10| + |15 - 2| = 18 。\n- 移除第 1 个点后,最大距离在点 (3, 10) 和 (10, 2) 之间,为 |3 - 10| + |10 - 2| = 15 。\n- 移除第 2 个点后,最大距离在点 (5, 15) 和 (4, 4) 之间,为 |5 - 4| + |15 - 4| = 12 。\n- 移除第 3 个点后,最大距离在点 (5, 15) 和 (10, 2) 之间的,为 |5 - 10| + |15 - 2| = 18 。\n在恰好移除一个点后,任意两点之间的最大距离可能的最小值是 12 。\n
\n\n

示例 2:

\n\n
\n输入:points = [[1,1],[1,1],[1,1]]\n输出:0\n解释:移除任一点后,任意两点之间的最大距离都是 0 。\n
\n\n

 

\n\n

提示:

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\n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "Kotlin", "langSlug": "kotlin", "code": "class Solution {\n fun minimumDistance(points: Array): Int {\n \n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "Dart", "langSlug": "dart", "code": "class Solution {\n int minimumDistance(List> points) {\n \n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "Go", "langSlug": "golang", "code": "func minimumDistance(points [][]int) int {\n \n}", "__typename": "CodeSnippetNode" }, { "lang": "Ruby", "langSlug": "ruby", "code": "# @param {Integer[][]} points\n# @return {Integer}\ndef minimum_distance(points)\n \nend", "__typename": "CodeSnippetNode" }, { "lang": "Scala", "langSlug": "scala", "code": "object Solution {\n def minimumDistance(points: Array[Array[Int]]): Int = {\n \n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "Rust", "langSlug": "rust", "code": "impl Solution {\n pub fn minimum_distance(points: Vec>) -> i32 {\n \n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "Racket", "langSlug": "racket", "code": "(define/contract (minimum-distance points)\n (-> (listof (listof exact-integer?)) exact-integer?)\n )", "__typename": "CodeSnippetNode" }, { "lang": "Erlang", "langSlug": "erlang", "code": "-spec minimum_distance(Points :: [[integer()]]) -> integer().\nminimum_distance(Points) ->\n .", "__typename": "CodeSnippetNode" }, { "lang": "Elixir", "langSlug": "elixir", "code": "defmodule Solution do\n @spec minimum_distance(points :: [[integer]]) :: integer\n def minimum_distance(points) do\n \n end\nend", "__typename": "CodeSnippetNode" }, { "lang": "Cangjie", "langSlug": "cangjie", "code": "class Solution {\n func minimumDistance(points: Array>): Int64 {\n\n }\n}", "__typename": "CodeSnippetNode" } ], "stats": "{\"totalAccepted\": \"12.6K\", \"totalSubmission\": \"23.3K\", \"totalAcceptedRaw\": 12597, \"totalSubmissionRaw\": 23314, \"acRate\": \"54.0%\"}", "hints": [ "Notice that the Manhattan distance between two points [xi, yi] and [xj, yj] is max({xi - xj + yi - yj, xi - xj - yi + yj, - xi + xj + yi - yj, - xi + xj - yi + yj}).", "If you replace points as [xi - yi, xi + yi] then the Manhattan distance is max(max(xi) - min(xi), max(yi) - min(yi)) over all i.", "After those observations, the problem just becomes a simulation. Create multiset of points [xi - yi, xi + yi], you can iterate on a point you might remove and get the maximum Manhattan distance over all other points." ], "solution": null, "status": null, "sampleTestCase": "[[3,10],[5,15],[10,2],[4,4]]", "metaData": "{\n \"name\": \"minimumDistance\",\n \"params\": [\n {\n \"name\": \"points\",\n \"type\": \"integer[][]\"\n }\n ],\n \"return\": {\n \"type\": \"integer\"\n }\n}", "judgerAvailable": true, "judgeType": "large", "mysqlSchemas": [], "enableRunCode": true, "envInfo": "{\"cpp\":[\"C++\",\"

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