{ "data": { "question": { "questionId": "2656", "questionFrontendId": "2588", "categoryTitle": "Algorithms", "boundTopicId": 2158411, "title": "Count the Number of Beautiful Subarrays", "titleSlug": "count-the-number-of-beautiful-subarrays", "content": "

You are given a 0-indexed integer array nums. In one operation, you can:

\n\n\n\n

A subarray is beautiful if it is possible to make all of its elements equal to 0 after applying the above operation any number of times.

\n\n

Return the number of beautiful subarrays in the array nums.

\n\n

A subarray is a contiguous non-empty sequence of elements within an array.

\n\n

 

\n

Example 1:

\n\n
\nInput: nums = [4,3,1,2,4]\nOutput: 2\nExplanation: There are 2 beautiful subarrays in nums: [4,3,1,2,4] and [4,3,1,2,4].\n- We can make all elements in the subarray [3,1,2] equal to 0 in the following way:\n  - Choose [3, 1, 2] and k = 1. Subtract 21 from both numbers. The subarray becomes [1, 1, 0].\n  - Choose [1, 1, 0] and k = 0. Subtract 20 from both numbers. The subarray becomes [0, 0, 0].\n- We can make all elements in the subarray [4,3,1,2,4] equal to 0 in the following way:\n  - Choose [4, 3, 1, 2, 4] and k = 2. Subtract 22 from both numbers. The subarray becomes [0, 3, 1, 2, 0].\n  - Choose [0, 3, 1, 2, 0] and k = 0. Subtract 20 from both numbers. The subarray becomes [0, 2, 0, 2, 0].\n  - Choose [0, 2, 0, 2, 0] and k = 1. Subtract 21 from both numbers. The subarray becomes [0, 0, 0, 0, 0].\n
\n\n

Example 2:

\n\n
\nInput: nums = [1,10,4]\nOutput: 0\nExplanation: There are no beautiful subarrays in nums.\n
\n\n

 

\n

Constraints:

\n\n\n", "translatedTitle": "统计美丽子数组数目", "translatedContent": "

给你一个下标从 0 开始的整数数组nums 。每次操作中,你可以:

\n\n\n\n

如果一个子数组内执行上述操作若干次后,该子数组可以变成一个全为 0 的数组,那么我们称它是一个 美丽 的子数组。

\n\n

请你返回数组 nums 中 美丽子数组 的数目。

\n\n

子数组是一个数组中一段连续 非空 的元素序列。

\n\n

 

\n\n

示例 1:

\n\n
\n输入:nums = [4,3,1,2,4]\n输出:2\n解释:nums 中有 2 个美丽子数组:[4,3,1,2,4] 和 [4,3,1,2,4] 。\n- 按照下述步骤,我们可以将子数组 [3,1,2] 中所有元素变成 0 :\n  - 选择 [3, 1, 2] 和 k = 1 。将 2 个数字都减去 21 ,子数组变成 [1, 1, 0] 。\n  - 选择 [1, 1, 0] 和 k = 0 。将 2 个数字都减去 20 ,子数组变成 [0, 0, 0] 。\n- 按照下述步骤,我们可以将子数组 [4,3,1,2,4] 中所有元素变成 0 :\n  - 选择 [4, 3, 1, 2, 4] 和 k = 2 。将 2 个数字都减去 22 ,子数组变成 [0, 3, 1, 2, 0] 。\n  - 选择 [0, 3, 1, 2, 0] 和 k = 0 。将 2 个数字都减去 20 ,子数组变成 [0, 2, 0, 2, 0] 。\n  - 选择 [0, 2, 0, 2, 0] 和 k = 1 。将 2 个数字都减去 21 ,子数组变成 [0, 0, 0, 0, 0] 。\n
\n\n

示例 2:

\n\n
\n输入:nums = [1,10,4]\n输出:0\n解释:nums 中没有任何美丽子数组。\n
\n\n

 

\n\n

提示:

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