You are given a 0-indexed circular string array words and a string target. A circular array means that the array's end connects to the array's beginning.
words[i] is words[(i + 1) % n] and the previous element of words[i] is words[(i - 1 + n) % n], where n is the length of words.Starting from startIndex, you can move to either the next word or the previous word with 1 step at a time.
Return the shortest distance needed to reach the string target. If the string target does not exist in words, return -1.
\n
Example 1:
\n\n\nInput: words = ["hello","i","am","leetcode","hello"], target = "hello", startIndex = 1\nOutput: 1\nExplanation: We start from index 1 and can reach "hello" by\n- moving 3 units to the right to reach index 4.\n- moving 2 units to the left to reach index 4.\n- moving 4 units to the right to reach index 0.\n- moving 1 unit to the left to reach index 0.\nThe shortest distance to reach "hello" is 1.\n\n\n
Example 2:
\n\n\nInput: words = ["a","b","leetcode"], target = "leetcode", startIndex = 0\nOutput: 1\nExplanation: We start from index 0 and can reach "leetcode" by\n- moving 2 units to the right to reach index 3.\n- moving 1 unit to the left to reach index 3.\nThe shortest distance to reach "leetcode" is 1.\n\n
Example 3:
\n\n\nInput: words = ["i","eat","leetcode"], target = "ate", startIndex = 0\nOutput: -1\nExplanation: Since "ate" does not exist in words, we return -1.\n\n\n\n
Constraints:
\n\n1 <= words.length <= 1001 <= words[i].length <= 100words[i] and target consist of only lowercase English letters.0 <= startIndex < words.lengthCompiled with clang 11 using the latest C++ 20 standard.
Your code is compiled with level two optimization (-O2). AddressSanitizer is also enabled to help detect out-of-bounds and use-after-free bugs.
Most standard library headers are already included automatically for your convenience.
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