Given the array favoriteCompanies where favoriteCompanies[i] is the list of favorites companies for the ith person (indexed from 0).
Return the indices of people whose list of favorite companies is not a subset of any other list of favorites companies. You must return the indices in increasing order.
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Example 1:
\n\n\nInput: favoriteCompanies = [["leetcode","google","facebook"],["google","microsoft"],["google","facebook"],["google"],["amazon"]]\nOutput: [0,1,4] \nExplanation: \nPerson with index=2 has favoriteCompanies[2]=["google","facebook"] which is a subset of favoriteCompanies[0]=["leetcode","google","facebook"] corresponding to the person with index 0. \nPerson with index=3 has favoriteCompanies[3]=["google"] which is a subset of favoriteCompanies[0]=["leetcode","google","facebook"] and favoriteCompanies[1]=["google","microsoft"]. \nOther lists of favorite companies are not a subset of another list, therefore, the answer is [0,1,4].\n\n\n
Example 2:
\n\n\nInput: favoriteCompanies = [["leetcode","google","facebook"],["leetcode","amazon"],["facebook","google"]]\nOutput: [0,1] \nExplanation: In this case favoriteCompanies[2]=["facebook","google"] is a subset of favoriteCompanies[0]=["leetcode","google","facebook"], therefore, the answer is [0,1].\n\n\n
Example 3:
\n\n\nInput: favoriteCompanies = [["leetcode"],["google"],["facebook"],["amazon"]]\nOutput: [0,1,2,3]\n\n\n
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Constraints:
\n\n1 <= favoriteCompanies.length <= 1001 <= favoriteCompanies[i].length <= 5001 <= favoriteCompanies[i][j].length <= 20favoriteCompanies[i] are distinct.favoriteCompanies[i] != favoriteCompanies[j].Compiled with clang 11 using the latest C++ 20 standard.
Your code is compiled with level two optimization (-O2). AddressSanitizer is also enabled to help detect out-of-bounds and use-after-free bugs.
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