{ "data": { "question": { "questionId": "3184", "questionFrontendId": "2926", "boundTopicId": null, "title": "Maximum Balanced Subsequence Sum", "titleSlug": "maximum-balanced-subsequence-sum", "content": "
You are given a 0-indexed integer array nums
.
A subsequence of nums
having length k
and consisting of indices i0 < i1 < ... < ik-1
is balanced if the following holds:
nums[ij] - nums[ij-1] >= ij - ij-1
, for every j
in the range [1, k - 1]
.A subsequence of nums
having length 1
is considered balanced.
Return an integer denoting the maximum possible sum of elements in a balanced subsequence of nums
.
A subsequence of an array is a new non-empty array that is formed from the original array by deleting some (possibly none) of the elements without disturbing the relative positions of the remaining elements.
\n\n\n
Example 1:
\n\n\nInput: nums = [3,3,5,6]\nOutput: 14\nExplanation: In this example, the subsequence [3,5,6] consisting of indices 0, 2, and 3 can be selected.\nnums[2] - nums[0] >= 2 - 0.\nnums[3] - nums[2] >= 3 - 2.\nHence, it is a balanced subsequence, and its sum is the maximum among the balanced subsequences of nums.\nThe subsequence consisting of indices 1, 2, and 3 is also valid.\nIt can be shown that it is not possible to get a balanced subsequence with a sum greater than 14.\n\n
Example 2:
\n\n\nInput: nums = [5,-1,-3,8]\nOutput: 13\nExplanation: In this example, the subsequence [5,8] consisting of indices 0 and 3 can be selected.\nnums[3] - nums[0] >= 3 - 0.\nHence, it is a balanced subsequence, and its sum is the maximum among the balanced subsequences of nums.\nIt can be shown that it is not possible to get a balanced subsequence with a sum greater than 13.\n\n\n
Example 3:
\n\n\nInput: nums = [-2,-1]\nOutput: -1\nExplanation: In this example, the subsequence [-1] can be selected.\nIt is a balanced subsequence, and its sum is the maximum among the balanced subsequences of nums.\n\n\n
\n
Constraints:
\n\n1 <= nums.length <= 105
-109 <= nums[i] <= 109
dp[x]
represent the maximum sum of a balanced subsequence ending at x
.",
"Rewriting the formula nums[ij] - nums[ij-1] >= ij - ij-1
gives nums[ij] - ij >= nums[ij-1] - ij-1
.",
"So, for some index x
, we need to find an index y
, y < x
, such that dp[x] = nums[x] + dp[y]
is maximized, and nums[x] - x >= nums[y] - y
.",
"There are many ways to achieve this. One method involves sorting the values of nums[x] - x
for all indices x
and using a segment/Fenwick tree with coordinate compression.",
"Hence, using a dictionary or map, let's call it dict
, where dict[nums[x] - x]
represents the position of the value, nums[x] - x
, in the segment tree.",
"The tree is initialized with zeros initially.",
"For indices x
in order from [0, n - 1]
, dp[x] = max(nums[x]
, nums[x]
+ the maximum query from the tree in the range [0, dict[nums[x] - x]])
, and if dp[x]
is greater than the value in the tree at position dict[nums[x] - x]
, we update the value in the tree.",
"The answer to the problem is the maximum value in dp
."
],
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