There exists an undirected tree with n nodes numbered 0 to n - 1. You are given a 2D integer array edges of length n - 1, where edges[i] = [ui, vi, wi] indicates that there is an edge between nodes ui and vi with weight wi in the tree.
Your task is to remove zero or more edges such that:
\n\nk other nodes, where k is given.Return the maximum possible sum of weights for the remaining edges after making the necessary removals.
\n\n\n
Example 1:
\n\nInput: edges = [[0,1,4],[0,2,2],[2,3,12],[2,4,6]], k = 2
\n\nOutput: 22
\n\nExplanation:
\n\n![\"\"](\"https://assets.leetcode.com/uploads/2024/10/30/test1drawio.png\")
[0, 2, 2], ensuring that no node has edges with more than k = 2 nodes.Example 2:
\n\nInput: edges = [[0,1,5],[1,2,10],[0,3,15],[3,4,20],[3,5,5],[0,6,10]], k = 3
\n\nOutput: 65
\n\nExplanation:
\n\nk = 3 nodes, we don't remove any edges.\n
Constraints:
\n\n2 <= n <= 1051 <= k <= n - 1edges.length == n - 1edges[i].length == 30 <= edges[i][0] <= n - 10 <= edges[i][1] <= n - 11 <= edges[i][2] <= 106edges form a valid tree.Compiled with clang 19 using the latest C++ 23 standard, and libstdc++ provided by GCC 14.
Your code is compiled with level two optimization (-O2). AddressSanitizer is also enabled to help detect out-of-bounds and use-after-free bugs.
Most standard library headers are already included automatically for your convenience.
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