![\"\"](\"https://assets.leetcode.com/uploads/2020/10/02/ex1.jpg\")
You are given an m x n matrix M initialized with all 0's and an array of operations ops, where ops[i] = [ai, bi] means M[x][y] should be incremented by one for all 0 <= x < ai and 0 <= y < bi.
Count and return the number of maximum integers in the matrix after performing all the operations.
\n\n\n
Example 1:
\n\n\nInput: m = 3, n = 3, ops = [[2,2],[3,3]]\nOutput: 4\nExplanation: The maximum integer in M is 2, and there are four of it in M. So return 4.\n\n\n
Example 2:
\n\n\nInput: m = 3, n = 3, ops = [[2,2],[3,3],[3,3],[3,3],[2,2],[3,3],[3,3],[3,3],[2,2],[3,3],[3,3],[3,3]]\nOutput: 4\n\n\n
Example 3:
\n\n\nInput: m = 3, n = 3, ops = []\nOutput: 9\n\n\n
\n
Constraints:
\n\n1 <= m, n <= 4 * 1040 <= ops.length <= 104ops[i].length == 21 <= ai <= m1 <= bi <= n给你一个 m x n 的矩阵 M 和一个操作数组 op 。矩阵初始化时所有的单元格都为 0 。ops[i] = [ai, bi] 意味着当所有的 0 <= x < ai 和 0 <= y < bi 时， M[x][y] 应该加 1。
在 执行完所有操作后 ，计算并返回 矩阵中最大整数的个数 。
\n\n\n\n
示例 1:
\n\n
\n输入: m = 3, n = 3，ops = [[2,2],[3,3]]\n输出: 4\n解释: M 中最大的整数是 2, 而且 M 中有4个值为2的元素。因此返回 4。\n\n\n
示例 2:
\n\n\n输入: m = 3, n = 3, ops = [[2,2],[3,3],[3,3],[3,3],[2,2],[3,3],[3,3],[3,3],[2,2],[3,3],[3,3],[3,3]]\n输出: 4\n\n\n
示例 3:
\n\n\n输入: m = 3, n = 3, ops = []\n输出: 9\n\n\n
\n\n
提示:
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