Given an integer array nums and an integer k, return the number of subarrays of nums where the least common multiple of the subarray's elements is k.
A subarray is a contiguous non-empty sequence of elements within an array.
\n\nThe least common multiple of an array is the smallest positive integer that is divisible by all the array elements.
\n\n\n
Example 1:
\n\n\nInput: nums = [3,6,2,7,1], k = 6\nOutput: 4\nExplanation: The subarrays of nums where 6 is the least common multiple of all the subarray's elements are:\n- [3,6,2,7,1]\n- [3,6,2,7,1]\n- [3,6,2,7,1]\n- [3,6,2,7,1]\n\n\n
Example 2:
\n\n\nInput: nums = [3], k = 2\nOutput: 0\nExplanation: There are no subarrays of nums where 2 is the least common multiple of all the subarray's elements.\n\n\n
\n
Constraints:
\n\n1 <= nums.length <= 10001 <= nums[i], k <= 1000给你一个整数数组 nums 和一个整数 k ，请你统计并返回 nums 的 子数组 中满足 元素最小公倍数为 k 的子数组数目。
子数组 是数组中一个连续非空的元素序列。
\n\n数组的最小公倍数 是可被所有数组元素整除的最小正整数。
\n\n\n\n
示例 1 ：
\n\n输入：nums = [3,6,2,7,1], k = 6\n输出：4\n解释：以 6 为最小公倍数的子数组是：\n- [3,6,2,7,1]\n- [3,6,2,7,1]\n- [3,6,2,7,1]\n- [3,6,2,7,1]\n\n\n
示例 2 ：
\n\n输入：nums = [3], k = 2\n输出：0\n解释：不存在以 2 为最小公倍数的子数组。\n\n\n
\n\n
提示：
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