You are given a 0-indexed integer array nums. In one operation, select any non-negative integer x and an index i, then update nums[i] to be equal to nums[i] AND (nums[i] XOR x).
Note that AND is the bitwise AND operation and XOR is the bitwise XOR operation.
Return the maximum possible bitwise XOR of all elements of nums after applying the operation any number of times.
\n
Example 1:
\n\n\nInput: nums = [3,2,4,6]\nOutput: 7\nExplanation: Apply the operation with x = 4 and i = 3, num[3] = 6 AND (6 XOR 4) = 6 AND 2 = 2.\nNow, nums = [3, 2, 4, 2] and the bitwise XOR of all the elements = 3 XOR 2 XOR 4 XOR 2 = 7.\nIt can be shown that 7 is the maximum possible bitwise XOR.\nNote that other operations may be used to achieve a bitwise XOR of 7.\n\n
Example 2:
\n\n\nInput: nums = [1,2,3,9,2]\nOutput: 11\nExplanation: Apply the operation zero times.\nThe bitwise XOR of all the elements = 1 XOR 2 XOR 3 XOR 9 XOR 2 = 11.\nIt can be shown that 11 is the maximum possible bitwise XOR.\n\n
\n
Constraints:
\n\n1 <= nums.length <= 1050 <= nums[i] <= 108给你一个下标从 0 开始的整数数组 nums 。一次操作中，选择 任意 非负整数 x 和一个下标 i ，更新 nums[i] 为 nums[i] AND (nums[i] XOR x) 。
注意，AND 是逐位与运算，XOR 是逐位异或运算。
请你执行 任意次 更新操作，并返回 nums 中所有元素 最大 逐位异或和。
\n\n
示例 1：
\n\n输入：nums = [3,2,4,6]\n输出：7\n解释：选择 x = 4 和 i = 3 进行操作，num[3] = 6 AND (6 XOR 4) = 6 AND 2 = 2 。\n现在，nums = [3, 2, 4, 2] 且所有元素逐位异或得到 3 XOR 2 XOR 4 XOR 2 = 7 。\n可知 7 是能得到的最大逐位异或和。\n注意，其他操作可能也能得到逐位异或和 7 。\n\n
示例 2：
\n\n输入：nums = [1,2,3,9,2]\n输出：11\n解释：执行 0 次操作。\n所有元素的逐位异或和为 1 XOR 2 XOR 3 XOR 9 XOR 2 = 11 。\n可知 11 是能得到的最大逐位异或和。\n\n
\n\n
提示：
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