You are given an integer num. You know that Bob will sneakily remap one of the 10 possible digits (0 to 9) to another digit.
Return the difference between the maximum and minimum values Bob can make by remapping exactly one digit in num.
Notes:
\n\nd1 in num with d2.num does not change.\n
Example 1:
\n\n\nInput: num = 11891\nOutput: 99009\nExplanation: \nTo achieve the maximum value, Bob can remap the digit 1 to the digit 9 to yield 99899.\nTo achieve the minimum value, Bob can remap the digit 1 to the digit 0, yielding 890.\nThe difference between these two numbers is 99009.\n\n\n
Example 2:
\n\n\nInput: num = 90\nOutput: 99\nExplanation:\nThe maximum value that can be returned by the function is 99 (if 0 is replaced by 9) and the minimum value that can be returned by the function is 0 (if 9 is replaced by 0).\nThus, we return 99.\n\n
\n
Constraints:
\n\n1 <= num <= 108给你一个整数 num 。你知道 Danny Mittal 会偷偷将 0 到 9 中的一个数字 替换 成另一个数字。
请你返回将 num 中 恰好一个 数字进行替换后，得到的最大值和最小值的差为多少。
注意：
\n\nd1 替换成另一个数字 d2 时，Danny 需要将 nums 中所有 d1 都替换成 d2 。num 可以不变。\n\n
示例 1：
\n\n\n输入：num = 11891\n输出：99009\n解释：\n为了得到最大值，我们将数字 1 替换成数字 9 ，得到 99899 。\n为了得到最小值，我们将数字 1 替换成数字 0 ，得到 890 。\n两个数字的差值为 99009 。\n\n\n
示例 2：
\n\n\n输入：num = 90\n输出：99\n解释：\n可以得到的最大值是 99（将 0 替换成 9），最小值是 0（将 9 替换成 0）。\n所以我们得到 99 。\n\n
\n\n
提示：
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