You are given two strings, word1 and word2. You want to construct a string in the following manner:
subsequence1 from word1.subsequence2 from word2.subsequence1 + subsequence2, to make the string.Return the length of the longest palindrome that can be constructed in the described manner. If no palindromes can be constructed, return 0.
A subsequence of a string s is a string that can be made by deleting some (possibly none) characters from s without changing the order of the remaining characters.
A palindrome is a string that reads the same forward as well as backward.
\n\n\n
Example 1:
\n\n\nInput: word1 = "cacb", word2 = "cbba"\nOutput: 5\nExplanation: Choose "ab" from word1 and "cba" from word2 to make "abcba", which is a palindrome.\n\n
Example 2:
\n\n\nInput: word1 = "ab", word2 = "ab"\nOutput: 3\nExplanation: Choose "ab" from word1 and "a" from word2 to make "aba", which is a palindrome.\n\n
Example 3:
\n\n\nInput: word1 = "aa", word2 = "bb"\nOutput: 0\nExplanation: You cannot construct a palindrome from the described method, so return 0.\n\n
\n
Constraints:
\n\n1 <= word1.length, word2.length <= 1000word1 and word2 consist of lowercase English letters.给你两个字符串 word1 和 word2 ，请你按下述方法构造一个字符串：
word1 中选出某个 非空 子序列 subsequence1 。word2 中选出某个 非空 子序列 subsequence2 。subsequence1 + subsequence2 ，得到字符串。返回可按上述方法构造的最长 回文串 的 长度 。如果无法构造回文串，返回 0 。
字符串 s 的一个 子序列 是通过从 s 中删除一些（也可能不删除）字符而不更改其余字符的顺序生成的字符串。
回文串 是正着读和反着读结果一致的字符串。
\n\n\n\n
示例 1：
\n\n输入：word1 = \"cacb\", word2 = \"cbba\"\n输出：5\n解释：从 word1 中选出 \"ab\" ，从 word2 中选出 \"cba\" ，得到回文串 \"abcba\" 。\n\n
示例 2：
\n\n输入：word1 = \"ab\", word2 = \"ab\"\n输出：3\n解释：从 word1 中选出 \"ab\" ，从 word2 中选出 \"a\" ，得到回文串 \"aba\" 。\n\n
示例 3：
\n\n输入：word1 = \"aa\", word2 = \"bb\"\n输出：0\n解释：无法按题面所述方法构造回文串，所以返回 0 。\n\n
\n\n
提示：
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