Given a binary string s, return true if the longest contiguous segment of 1's is strictly longer than the longest contiguous segment of 0's in s, or return false otherwise.
s = "110100010" the longest continuous segment of 1s has length 2, and the longest continuous segment of 0s has length 3.Note that if there are no 0's, then the longest continuous segment of 0's is considered to have a length 0. The same applies if there is no 1's.
\n
Example 1:
\n\n\nInput: s = "1101"\nOutput: true\nExplanation:\nThe longest contiguous segment of 1s has length 2: "1101"\nThe longest contiguous segment of 0s has length 1: "1101"\nThe segment of 1s is longer, so return true.\n\n\n
Example 2:
\n\n\nInput: s = "111000"\nOutput: false\nExplanation:\nThe longest contiguous segment of 1s has length 3: "111000"\nThe longest contiguous segment of 0s has length 3: "111000"\nThe segment of 1s is not longer, so return false.\n\n\n
Example 3:
\n\n\nInput: s = "110100010"\nOutput: false\nExplanation:\nThe longest contiguous segment of 1s has length 2: "110100010"\nThe longest contiguous segment of 0s has length 3: "110100010"\nThe segment of 1s is not longer, so return false.\n\n\n
\n
Constraints:
\n\n1 <= s.length <= 100s[i] is either '0' or '1'.给你一个二进制字符串 s 。如果字符串中由 1 组成的 最长 连续子字符串 严格长于 由 0 组成的 最长 连续子字符串，返回 true ；否则，返回 false 。
s = \"110100010\" 中，由 1 组成的最长连续子字符串的长度是 2 ，由 0 组成的最长连续子字符串的长度是 3 。注意，如果字符串中不存在 0 ，此时认为由 0 组成的最长连续子字符串的长度是 0 。字符串中不存在 1 的情况也适用此规则。
\n\n
示例 1：
\n\n\n输入：s = \"1101\"\n输出：true\n解释：\n由\n\n1组成的最长连续子字符串的长度是 2：\"1101\"\n由0组成的最长连续子字符串的长度是 1：\"1101\"\n由 1 组成的子字符串更长，故返回 true 。\n
示例 2：
\n\n\n输入：s = \"111000\"\n输出：false\n解释：\n由\n\n1组成的最长连续子字符串的长度是 3：\"111000\"\n由0组成的最长连续子字符串的长度是 3：\"111000\"\n由 1 组成的子字符串不比由 0 组成的子字符串长，故返回 false 。\n
示例 3：
\n\n\n输入：s = \"110100010\"\n输出：false\n解释：\n由\n\n1组成的最长连续子字符串的长度是 2：\"110100010\"\n由0组成的最长连续子字符串的长度是 3：\"110100010\"\n由 1 组成的子字符串不比由 0 组成的子字符串长，故返回 false 。\n
\n\n
提示：
\n\n1 <= s.length <= 100s[i] 不是 '0' 就是 '1'\\u7248\\u672c\\uff1a \\u7f16\\u8bd1\\u65f6\\uff0c\\u5c06\\u4f1a\\u91c7\\u7528 \\u4e3a\\u4e86\\u4f7f\\u7528\\u65b9\\u4fbf\\uff0c\\u5927\\u90e8\\u5206\\u6807\\u51c6\\u5e93\\u7684\\u5934\\u6587\\u4ef6\\u5df2\\u7ecf\\u88ab\\u81ea\\u52a8\\u5bfc\\u5165\\u3002<\\/p>\"],\"java\":[\"Java\",\" \\u7248\\u672c\\uff1a \\u4e3a\\u4e86\\u65b9\\u4fbf\\u8d77\\u89c1\\uff0c\\u5927\\u90e8\\u5206\\u6807\\u51c6\\u5e93\\u7684\\u5934\\u6587\\u4ef6\\u5df2\\u88ab\\u5bfc\\u5165\\u3002<\\/p>\\r\\n\\r\\n \\u5305\\u542b Pair \\u7c7b: https:\\/\\/docs.oracle.com\\/javase\\/8\\/javafx\\/api\\/javafx\\/util\\/Pair.html <\\/p>\"],\"python\":[\"Python\",\" \\u7248\\u672c\\uff1a \\u4e3a\\u4e86\\u65b9\\u4fbf\\u8d77\\u89c1\\uff0c\\u5927\\u90e8\\u5206\\u5e38\\u7528\\u5e93\\u5df2\\u7ecf\\u88ab\\u81ea\\u52a8 \\u5bfc\\u5165\\uff0c\\u5982\\uff1aarray<\\/a>, bisect<\\/a>, collections<\\/a>\\u3002\\u5982\\u679c\\u60a8\\u9700\\u8981\\u4f7f\\u7528\\u5176\\u4ed6\\u5e93\\u51fd\\u6570\\uff0c\\u8bf7\\u81ea\\u884c\\u5bfc\\u5165\\u3002<\\/p>\\r\\n\\r\\n \\u6ce8\\u610f Python 2.7 \\u5df2\\u4e0d\\u518d\\u7ef4\\u62a4<\\/a>\\u3002 \\u5982\\u60f3\\u4f7f\\u7528\\u6700\\u65b0\\u7248\\u7684Python\\uff0c\\u8bf7\\u9009\\u62e9Python 3\\u3002<\\/p>\"],\"c\":[\"C\",\" \\u7248\\u672c\\uff1a \\u7f16\\u8bd1\\u65f6\\uff0c\\u5c06\\u4f1a\\u91c7\\u7528 \\u4e3a\\u4e86\\u4f7f\\u7528\\u65b9\\u4fbf\\uff0c\\u5927\\u90e8\\u5206\\u6807\\u51c6\\u5e93\\u7684\\u5934\\u6587\\u4ef6\\u5df2\\u7ecf\\u88ab\\u81ea\\u52a8\\u5bfc\\u5165\\u3002<\\/p>\\r\\n\\r\\n \\u5982\\u60f3\\u4f7f\\u7528\\u54c8\\u5e0c\\u8868\\u8fd0\\u7b97, \\u60a8\\u53ef\\u4ee5\\u4f7f\\u7528 uthash<\\/a>\\u3002 \\\"uthash.h\\\"\\u5df2\\u7ecf\\u9ed8\\u8ba4\\u88ab\\u5bfc\\u5165\\u3002\\u8bf7\\u770b\\u5982\\u4e0b\\u793a\\u4f8b:<\\/p>\\r\\n\\r\\n 1. 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"book": null,
"isSubscribed": false,
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"dailyRecordStatus": null,
"editorType": "CKEDITOR",
"ugcQuestionId": null,
"style": "LEETCODE",
"exampleTestcases": "\"1101\"\n\"111000\"\n\"110100010\"",
"__typename": "QuestionNode"
}
}
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