(This problem is an interactive problem.)
\n\nYou may recall that an array arr is a mountain array if and only if:
arr.length >= 3i with 0 < i < arr.length - 1 such that:\n\tarr[0] < arr[1] < ... < arr[i - 1] < arr[i]arr[i] > arr[i + 1] > ... > arr[arr.length - 1]Given a mountain array mountainArr, return the minimum index such that mountainArr.get(index) == target. If such an index does not exist, return -1.
You cannot access the mountain array directly. You may only access the array using a MountainArray interface:
MountainArray.get(k) returns the element of the array at index k (0-indexed).MountainArray.length() returns the length of the array.Submissions making more than 100 calls to MountainArray.get will be judged Wrong Answer. Also, any solutions that attempt to circumvent the judge will result in disqualification.
\n
Example 1:
\n\n\nInput: mountainArr = [1,2,3,4,5,3,1], target = 3\nOutput: 2\nExplanation: 3 exists in the array, at index=2 and index=5. Return the minimum index, which is 2.\n\n
Example 2:
\n\n\nInput: mountainArr = [0,1,2,4,2,1], target = 3\nOutput: -1\nExplanation: 3 does not exist in the array, so we return -1.\n\n\n\n
Constraints:
\n\n3 <= mountainArr.length() <= 1040 <= target <= 1090 <= mountainArr.get(index) <= 109（这是一个 交互式问题 ）
\n\n你可以将一个数组 arr 称为 山脉数组 当且仅当：
arr.length >= 30 < i < arr.length - 1 的 i 使得：\n\tarr[0] < arr[1] < ... < arr[i - 1] < arr[i]arr[i] > arr[i + 1] > ... > arr[arr.length - 1]给定一个山脉数组 mountainArr ，返回 最小 的 index 使得 mountainArr.get(index) == target。如果不存在这样的 index，返回 -1 。
你无法直接访问山脉数组。你只能使用 MountainArray 接口来访问数组：
MountainArray.get(k) 返回数组中下标为 k 的元素（从 0 开始）。MountainArray.length() 返回数组的长度。调用 MountainArray.get 超过 100 次的提交会被判定为错误答案。此外，任何试图绕过在线评测的解决方案都将导致取消资格。
\n\n
示例 1：
\n\n\n输入：mountainArr = [1,2,3,4,5,3,1], target = 3\n输出：2\n解释：3 在数组中出现了两次，下标分别为 2 和 5，我们返回最小的下标 2。\n\n
示例 2：
\n\n\n输入：mountainArr = [0,1,2,4,2,1], target = 3\n输出：-1\n解释：3 在数组中没有出现，返回 -1。\n\n\n
\n\n
提示：
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