{ "data": { "question": { "questionId": "1530", "questionFrontendId": "1433", "categoryTitle": "Algorithms", "boundTopicId": 226091, "title": "Check If a String Can Break Another String", "titleSlug": "check-if-a-string-can-break-another-string", "content": "
Given two strings: s1
and s2
with the same size, check if some permutation of string s1
can break some permutation of string s2
or vice-versa. In other words s2
can break s1
or vice-versa.
A string x
can break string y
(both of size n
) if x[i] >= y[i]
(in alphabetical order) for all i
between 0
and n-1
.
\n
Example 1:
\n\n\nInput: s1 = "abc", s2 = "xya"\nOutput: true\nExplanation: "ayx" is a permutation of s2="xya" which can break to string "abc" which is a permutation of s1="abc".\n\n\n
Example 2:
\n\n\nInput: s1 = "abe", s2 = "acd"\nOutput: false \nExplanation: All permutations for s1="abe" are: "abe", "aeb", "bae", "bea", "eab" and "eba" and all permutation for s2="acd" are: "acd", "adc", "cad", "cda", "dac" and "dca". However, there is not any permutation from s1 which can break some permutation from s2 and vice-versa.\n\n\n
Example 3:
\n\n\nInput: s1 = "leetcodee", s2 = "interview"\nOutput: true\n\n\n
\n
Constraints:
\n\ns1.length == n
s2.length == n
1 <= n <= 10^5
给你两个字符串 s1
和 s2
,它们长度相等,请你检查是否存在一个 s1
的排列可以打破 s2
的一个排列,或者是否存在一个 s2
的排列可以打破 s1
的一个排列。
字符串 x
可以打破字符串 y
(两者长度都为 n
)需满足对于所有 i
(在 0
到 n - 1
之间)都有 x[i] >= y[i]
(字典序意义下的顺序)。
\n\n
示例 1:
\n\n输入:s1 = "abc", s2 = "xya"\n输出:true\n解释:"ayx" 是 s2="xya" 的一个排列,"abc" 是字符串 s1="abc" 的一个排列,且 "ayx" 可以打破 "abc" 。\n\n\n
示例 2:
\n\n输入:s1 = "abe", s2 = "acd"\n输出:false \n解释:s1="abe" 的所有排列包括:"abe","aeb","bae","bea","eab" 和 "eba" ,s2="acd" 的所有排列包括:"acd","adc","cad","cda","dac" 和 "dca"。然而没有任何 s1 的排列可以打破 s2 的排列。也没有 s2 的排列能打破 s1 的排列。\n\n\n
示例 3:
\n\n输入:s1 = "leetcodee", s2 = "interview"\n输出:true\n\n\n
\n\n
提示:
\n\ns1.length == n
s2.length == n
1 <= n <= 10^5
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"book": null,
"isSubscribed": false,
"isDailyQuestion": false,
"dailyRecordStatus": null,
"editorType": "CKEDITOR",
"ugcQuestionId": null,
"style": "LEETCODE",
"exampleTestcases": "\"abc\"\n\"xya\"\n\"abe\"\n\"acd\"\n\"leetcodee\"\n\"interview\"",
"__typename": "QuestionNode"
}
}
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