You are given a 0-indexed string word and an integer k.
At every second, you must perform the following operations:
\n\nk characters of word.k characters to the end of word.Note that you do not necessarily need to add the same characters that you removed. However, you must perform both operations at every second.
\n\nReturn the minimum time greater than zero required for word to revert to its initial state.
\n
Example 1:
\n\n\nInput: word = "abacaba", k = 3\nOutput: 2\nExplanation: At the 1st second, we remove characters "aba" from the prefix of word, and add characters "bac" to the end of word. Thus, word becomes equal to "cababac".\nAt the 2nd second, we remove characters "cab" from the prefix of word, and add "aba" to the end of word. Thus, word becomes equal to "abacaba" and reverts to its initial state.\nIt can be shown that 2 seconds is the minimum time greater than zero required for word to revert to its initial state.\n\n\n
Example 2:
\n\n\nInput: word = "abacaba", k = 4\nOutput: 1\nExplanation: At the 1st second, we remove characters "abac" from the prefix of word, and add characters "caba" to the end of word. Thus, word becomes equal to "abacaba" and reverts to its initial state.\nIt can be shown that 1 second is the minimum time greater than zero required for word to revert to its initial state.\n\n\n
Example 3:
\n\n\nInput: word = "abcbabcd", k = 2\nOutput: 4\nExplanation: At every second, we will remove the first 2 characters of word, and add the same characters to the end of word.\nAfter 4 seconds, word becomes equal to "abcbabcd" and reverts to its initial state.\nIt can be shown that 4 seconds is the minimum time greater than zero required for word to revert to its initial state.\n\n\n
\n
Constraints:
\n\n1 <= word.length <= 50 1 <= k <= word.lengthword consists only of lowercase English letters.k."
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