You are given a 0-indexed array nums and an integer target.
A 0-indexed array infinite_nums is generated by infinitely appending the elements of nums to itself.
Return the length of the shortest subarray of the array infinite_nums with a sum equal to target. If there is no such subarray return -1.
\n
Example 1:
\n\n\nInput: nums = [1,2,3], target = 5\nOutput: 2\nExplanation: In this example infinite_nums = [1,2,3,1,2,3,1,2,...].\nThe subarray in the range [1,2], has the sum equal to target = 5 and length = 2.\nIt can be proven that 2 is the shortest length of a subarray with sum equal to target = 5.\n\n\n
Example 2:
\n\n\nInput: nums = [1,1,1,2,3], target = 4\nOutput: 2\nExplanation: In this example infinite_nums = [1,1,1,2,3,1,1,1,2,3,1,1,...].\nThe subarray in the range [4,5], has the sum equal to target = 4 and length = 2.\nIt can be proven that 2 is the shortest length of a subarray with sum equal to target = 4.\n\n\n
Example 3:
\n\n\nInput: nums = [2,4,6,8], target = 3\nOutput: -1\nExplanation: In this example infinite_nums = [2,4,6,8,2,4,6,8,...].\nIt can be proven that there is no subarray with sum equal to target = 3.\n\n\n
\n
Constraints:
\n\n1 <= nums.length <= 1051 <= nums[i] <= 1051 <= target <= 109target is either: A subarray of nums, or prefix_sum[i] + k * sum(nums) + suffix_sum[j] for some i, j, k.",
"You can solve the problem for those two separate cases using hash map and prefix sums."
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