You are given a 0-indexed integer array nums.
nums is the minimum value of |nums[i] - nums[j]| over all 0 <= i < j < nums.length.nums is the maximum value of |nums[i] - nums[j]| over all 0 <= i < j < nums.length.nums is the sum of the high and low scores of nums.To minimize the score of nums, we can change the value of at most two elements of nums.
Return the minimum possible score after changing the value of at most two elements of nums.
Note that |x| denotes the absolute value of x.
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Example 1:
\n\n\nInput: nums = [1,4,3]\nOutput: 0\nExplanation: Change value of nums[1] and nums[2] to 1 so that nums becomes [1,1,1]. Now, the value of |nums[i] - nums[j]| is always equal to 0, so we return 0 + 0 = 0.\n\n\nExample 2:
\n\n\nInput: nums = [1,4,7,8,5]\nOutput: 3\nExplanation: Change nums[0] and nums[1] to be 6. Now nums becomes [6,6,7,8,5].\nOur low score is achieved when i = 0 and j = 1, in which case |\n\nnums[i] - nums[j]| = |6 - 6| = 0.\nOur high score is achieved when i = 3 and j = 4, in which case |nums[i] - nums[j]| = |8 - 5| = 3.\nThe sum of our high and low score is 3, which we can prove to be minimal.\n
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Constraints:
\n\n3 <= nums.length <= 1051 <= nums[i] <= 109Compiled with clang 11 using the latest C++ 20 standard.
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Most standard library headers are already included automatically for your convenience.
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