{ "data": { "question": { "questionId": "3313", "questionFrontendId": "3077", "boundTopicId": null, "title": "Maximum Strength of K Disjoint Subarrays", "titleSlug": "maximum-strength-of-k-disjoint-subarrays", "content": "

You are given a 0-indexed array of integers nums of length n, and a positive odd integer k.

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The strength of x subarrays is defined as strength = sum[1] * x - sum[2] * (x - 1) + sum[3] * (x - 2) - sum[4] * (x - 3) + ... + sum[x] * 1 where sum[i] is the sum of the elements in the ith subarray. Formally, strength is sum of (-1)i+1 * sum[i] * (x - i + 1) over all i's such that 1 <= i <= x.

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You need to select k disjoint subarrays from nums, such that their strength is maximum.

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Return the maximum possible strength that can be obtained.

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Note that the selected subarrays don't need to cover the entire array.

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Example 1:

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\nInput: nums = [1,2,3,-1,2], k = 3\nOutput: 22\nExplanation: The best possible way to select 3 subarrays is: nums[0..2], nums[3..3], and nums[4..4]. The strength is (1 + 2 + 3) * 3 - (-1) * 2 + 2 * 1 = 22.\n
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Example 2:

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\nInput: nums = [12,-2,-2,-2,-2], k = 5\nOutput: 64\nExplanation: The only possible way to select 5 disjoint subarrays is: nums[0..0], nums[1..1], nums[2..2], nums[3..3], and nums[4..4]. The strength is 12 * 5 - (-2) * 4 + (-2) * 3 - (-2) * 2 + (-2) * 1 = 64.\n
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Example 3:

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\nInput: nums = [-1,-2,-3], k = 1\nOutput: -1\nExplanation: The best possible way to select 1 subarray is: nums[0..0]. The strength is -1.\n
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Constraints:

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