You are given two strings s and p where p is a subsequence of s. You are also given a distinct 0-indexed integer array removable containing a subset of indices of s (s is also 0-indexed).
You want to choose an integer k (0 <= k <= removable.length) such that, after removing k characters from s using the first k indices in removable, p is still a subsequence of s. More formally, you will mark the character at s[removable[i]] for each 0 <= i < k, then remove all marked characters and check if p is still a subsequence.
Return the maximum k you can choose such that p is still a subsequence of s after the removals.
A subsequence of a string is a new string generated from the original string with some characters (can be none) deleted without changing the relative order of the remaining characters.
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Example 1:
\n\n\nInput: s = "abcacb", p = "ab", removable = [3,1,0]\nOutput: 2\nExplanation: After removing the characters at indices 3 and 1, "a\n\nbcacb" becomes "accb".\n"ab" is a subsequence of "accb".\nIf we remove the characters at indices 3, 1, and 0, "abcacb" becomes "ccb", and "ab" is no longer a subsequence.\nHence, the maximum k is 2.\n
Example 2:
\n\n\nInput: s = "abcbddddd", p = "abcd", removable = [3,2,1,4,5,6]\nOutput: 1\nExplanation: After removing the character at index 3, "abc\n\nbddddd" becomes "abcddddd".\n"abcd" is a subsequence of "abcddddd".\n
Example 3:
\n\n\nInput: s = "abcab", p = "abc", removable = [0,1,2,3,4]\nOutput: 0\nExplanation: If you remove the first index in the array removable, "abc" is no longer a subsequence.\n\n\n
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Constraints:
\n\n1 <= p.length <= s.length <= 1050 <= removable.length < s.length0 <= removable[i] < s.lengthp is a subsequence of s.s and p both consist of lowercase English letters.removable are distinct.Compiled with clang 11 using the latest C++ 20 standard.
Your code is compiled with level two optimization (-O2). AddressSanitizer is also enabled to help detect out-of-bounds and use-after-free bugs.
Most standard library headers are already included automatically for your convenience.
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