{ "data": { "question": { "questionId": "3464", "questionFrontendId": "3196", "boundTopicId": null, "title": "Maximize Total Cost of Alternating Subarrays", "titleSlug": "maximize-total-cost-of-alternating-subarrays", "content": "
You are given an integer array nums
with length n
.
The cost of a subarray nums[l..r]
, where 0 <= l <= r < n
, is defined as:
cost(l, r) = nums[l] - nums[l + 1] + ... + nums[r] * (−1)r − l
Your task is to split nums
into subarrays such that the total cost of the subarrays is maximized, ensuring each element belongs to exactly one subarray.
Formally, if nums
is split into k
subarrays, where k > 1
, at indices i1, i2, ..., ik − 1
, where 0 <= i1 < i2 < ... < ik - 1 < n - 1
, then the total cost will be:
cost(0, i1) + cost(i1 + 1, i2) + ... + cost(ik − 1 + 1, n − 1)
Return an integer denoting the maximum total cost of the subarrays after splitting the array optimally.
\n\nNote: If nums
is not split into subarrays, i.e. k = 1
, the total cost is simply cost(0, n - 1)
.
\n
Example 1:
\n\nInput: nums = [1,-2,3,4]
\n\nOutput: 10
\n\nExplanation:
\n\nOne way to maximize the total cost is by splitting [1, -2, 3, 4]
into subarrays [1, -2, 3]
and [4]
. The total cost will be (1 + 2 + 3) + 4 = 10
.
Example 2:
\n\nInput: nums = [1,-1,1,-1]
\n\nOutput: 4
\n\nExplanation:
\n\nOne way to maximize the total cost is by splitting [1, -1, 1, -1]
into subarrays [1, -1]
and [1, -1]
. The total cost will be (1 + 1) + (1 + 1) = 4
.
Example 3:
\n\nInput: nums = [0]
\n\nOutput: 0
\n\nExplanation:
\n\nWe cannot split the array further, so the answer is 0.
\nExample 4:
\n\nInput: nums = [1,-1]
\n\nOutput: 2
\n\nExplanation:
\n\nSelecting the whole array gives a total cost of 1 + 1 = 2
, which is the maximum.
\n
Constraints:
\n\n1 <= nums.length <= 105
-109 <= nums[i] <= 109
dp[i][0/1]
be the largest sum we can get for prefix nums[0..i]
, where dp[i][0]
is the maximum if the ith
element wasn't flipped, and dp[i][1]
is the maximum if the ith
element was flipped.",
"Based on the restriction:dp[i][0] = min(dp[i - 1][0], dp[i - 1][1]) + nums[i]
dp[i][1] = dp[i - 1][0] - nums[i]
",
"The initial state is:dp[1][0] = nums[0] + nums[1]
dp[1][1] = nums[0] - nums[1]
max(dp[n - 1][0], dp[n - 1][1])
.",
"Can you optimize the space complexity?"
],
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"status": null,
"sampleTestCase": "[1,-2,3,4]",
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