You are given a 0-indexed integer array nums and an integer k. You have a starting score of 0.
In one operation:
\n\ni such that 0 <= i < nums.length,nums[i], andnums[i] with ceil(nums[i] / 3).Return the maximum possible score you can attain after applying exactly k operations.
The ceiling function ceil(val) is the least integer greater than or equal to val.
\n
Example 1:
\n\n\nInput: nums = [10,10,10,10,10], k = 5\nOutput: 50\nExplanation: Apply the operation to each array element exactly once. The final score is 10 + 10 + 10 + 10 + 10 = 50.\n\n\n
Example 2:
\n\n\nInput: nums = [1,10,3,3,3], k = 3\nOutput: 17\nExplanation: You can do the following operations:\nOperation 1: Select i = 1, so nums becomes [1,4,3,3,3]. Your score increases by 10.\nOperation 2: Select i = 1, so nums becomes [1,2,3,3,3]. Your score increases by 4.\nOperation 3: Select i = 2, so nums becomes [1,1,1,3,3]. Your score increases by 3.\nThe final score is 10 + 4 + 3 = 17.\n\n\n
\n
Constraints:
\n\n1 <= nums.length, k <= 1051 <= nums[i] <= 109Compiled with clang 11 using the latest C++ 20 standard.
Your code is compiled with level two optimization (-O2). AddressSanitizer is also enabled to help detect out-of-bounds and use-after-free bugs.
Most standard library headers are already included automatically for your convenience.
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Python 2.7.12.
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