You are given a 0-indexed integer array nums and an integer k.
A subarray is called equal if all of its elements are equal. Note that the empty subarray is an equal subarray.
\n\nReturn the length of the longest possible equal subarray after deleting at most k elements from nums.
A subarray is a contiguous, possibly empty sequence of elements within an array.
\n\n\n
Example 1:
\n\n\nInput: nums = [1,3,2,3,1,3], k = 3\nOutput: 3\nExplanation: It's optimal to delete the elements at index 2 and index 4.\nAfter deleting them, nums becomes equal to [1, 3, 3, 3].\nThe longest equal subarray starts at i = 1 and ends at j = 3 with length equal to 3.\nIt can be proven that no longer equal subarrays can be created.\n\n\n
Example 2:
\n\n\nInput: nums = [1,1,2,2,1,1], k = 2\nOutput: 4\nExplanation: It's optimal to delete the elements at index 2 and index 3.\nAfter deleting them, nums becomes equal to [1, 1, 1, 1].\nThe array itself is an equal subarray, so the answer is 4.\nIt can be proven that no longer equal subarrays can be created.\n\n\n
\n
Constraints:
\n\n1 <= nums.length <= 1051 <= nums[i] <= nums.length0 <= k <= nums.lengthx in nums, create a sorted list indicesx of all indices i such that nums[i] == x.indicesx, execute a sliding window technique.indicesx, find i, j such that (indicesx[j] - indicesx[i]) - (j - i) <= k and j - i + 1 is maximized.j - i + 1 for all indicesx.Compiled with clang 11 using the latest C++ 20 standard.
Your code is compiled with level two optimization (-O2). AddressSanitizer is also enabled to help detect out-of-bounds and use-after-free bugs.
Most standard library headers are already included automatically for your convenience.
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