Given the root of a binary tree with unique values and the values of two different nodes of the tree x and y, return true if the nodes corresponding to the values x and y in the tree are cousins, or false otherwise.
Two nodes of a binary tree are cousins if they have the same depth with different parents.
\n\nNote that in a binary tree, the root node is at the depth 0, and children of each depth k node are at the depth k + 1.
\n
Example 1:
\n![\"\"](\"https://assets.leetcode.com/uploads/2019/02/12/q1248-01.png\")
\n\nInput: root = [1,2,3,4], x = 4, y = 3\nOutput: false\n\n\n
Example 2:
\n![\"\"](\"https://assets.leetcode.com/uploads/2019/02/12/q1248-02.png\")
\n\nInput: root = [1,2,3,null,4,null,5], x = 5, y = 4\nOutput: true\n\n\n
Example 3:
\n![\"\"](\"https://assets.leetcode.com/uploads/2019/02/13/q1248-03.png\")
\n\nInput: root = [1,2,3,null,4], x = 2, y = 3\nOutput: false\n\n\n
\n
Constraints:
\n\n[2, 100].1 <= Node.val <= 100x != yx and y are exist in the tree.Compiled with clang 11 using the latest C++ 20 standard.
Your code is compiled with level two optimization (-O2). AddressSanitizer is also enabled to help detect out-of-bounds and use-after-free bugs.
Most standard library headers are already included automatically for your convenience.
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