{ "data": { "question": { "questionId": "3928", "questionFrontendId": "3690", "categoryTitle": "Algorithms", "boundTopicId": 3786882, "title": "Split and Merge Array Transformation", "titleSlug": "split-and-merge-array-transformation", "content": "
You are given two integer arrays nums1
and nums2
, each of length n
. You may perform the following split-and-merge operation on nums1
any number of times:
nums1[L..R]
.nums1[0..L-1]
(empty if L = 0
) and the suffix nums1[R+1..n-1]
(empty if R = n - 1
).Return the minimum number of split-and-merge operations needed to transform nums1
into nums2
.
\n
Example 1:
\n\nInput: nums1 = [3,1,2], nums2 = [1,2,3]
\n\nOutput: 1
\n\nExplanation:
\n\n[3]
(L = 0
, R = 0
); the remaining array is [1,2]
.[3]
at the end; the array becomes [1,2,3]
.Example 2:
\n\nInput: nums1 = [1,1,2,3,4,5], nums2 = [5,4,3,2,1,1]
\n\nOutput: 3
\n\nExplanation:
\n\n[1,1,2]
at indices 0 - 2
; remaining is [3,4,5]
; insert [1,1,2]
at position 2
, resulting in [3,4,1,1,2,5]
.[4,1,1]
at indices 1 - 3
; remaining is [3,2,5]
; insert [4,1,1]
at position 3
, resulting in [3,2,5,4,1,1]
.[3,2]
at indices 0 - 1
; remaining is [5,4,1,1]
; insert [3,2]
at position 2
, resulting in [5,4,3,2,1,1]
.\n
Constraints:
\n\n2 <= n == nums1.length == nums2.length <= 6
-105 <= nums1[i], nums2[i] <= 105
nums2
is a permutation of nums1
.给你两个长度为 n
的整数数组 nums1
和 nums2
。你可以对 nums1
执行任意次下述的 拆分合并操作:
nums1[L..R]
。nums1[0..L-1]
(如果 L = 0
则为空)和后缀 nums1[R+1..n-1]
(如果 R = n - 1
则为空)。返回将 nums1
转换为 nums2
所需的 最少拆分合并操作 次数。
\n\n
示例 1:
\n\n输入: nums1 = [3,1,2], nums2 = [1,2,3]
\n\n输出: 1
\n\n解释:
\n\n[3]
(L = 0
, R = 0
);剩余数组为 [1,2]
。[3]
插入到末尾;数组变为 [1,2,3]
。示例 2:
\n\n输入: nums1 = [1,1,2,3,4,5], nums2 = [5,4,3,2,1,1]
\n\n输出: 3
\n\n解释:
\n\n0 - 2
处的 [1,1,2]
;剩余 [3,4,5]
;将 [1,1,2]
插入到位置 2
,得到 [3,4,1,1,2,5]
。1 - 3
处的 [4,1,1]
;剩余 [3,2,5]
;将 [4,1,1]
插入到位置 3
,得到 [3,2,5,4,1,1]
。0 - 1
处的 [3,2]
;剩余 [5,4,1,1]
;将 [3,2]
插入到位置 2
,得到 [5,4,3,2,1,1]
。\n\n
提示:
\n\n2 <= n == nums1.length == nums2.length <= 6
-105 <= nums1[i], nums2[i] <= 105
nums2
是 nums1
的一个 排列。BFS
over the space of array states, starting from nums1
and aiming for nums2
.",
"Represent each state as an array (or tuple) and enqueue it alongside its current operation count.",
"Maintain a visited set (e.g. a hash set or dictionary keyed by the state) to avoid revisiting the same configuration.",
"For each dequeued state, generate all possible \"split-and-merge\" successors by choosing every valid subarray [L..R]
, removing it, and inserting it at every possible position.",
"Stop as soon as you dequeue nums2
, and return its associated operation count."
],
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