You are given a 0-indexed integer array nums and an integer value.
In one operation, you can add or subtract value from any element of nums.
nums = [1,2,3] and value = 2, you can choose to subtract value from nums[0] to make nums = [-1,2,3].The MEX (minimum excluded) of an array is the smallest missing non-negative integer in it.
\n\n[-1,2,3] is 0 while the MEX of [1,0,3] is 2.Return the maximum MEX of nums after applying the mentioned operation any number of times.
\n
Example 1:
\n\n\nInput: nums = [1,-10,7,13,6,8], value = 5\nOutput: 4\nExplanation: One can achieve this result by applying the following operations:\n- Add value to nums[1] twice to make nums = [1,0,7,13,6,8]\n- Subtract value from nums[2] once to make nums = [1,0,2,13,6,8]\n- Subtract value from nums[3] twice to make nums = [1,0,2,3,6,8]\nThe MEX of nums is 4. It can be shown that 4 is the maximum MEX we can achieve.\n\n\n
Example 2:
\n\n\nInput: nums = [1,-10,7,13,6,8], value = 7\nOutput: 2\nExplanation: One can achieve this result by applying the following operation:\n- subtract value from nums[2] once to make nums = [1,-10,0,13,6,8]\nThe MEX of nums is 2. It can be shown that 2 is the maximum MEX we can achieve.\n\n\n
\n
Constraints:
\n\n1 <= nums.length, value <= 105-109 <= nums[i] <= 109给你一个下标从 0 开始的整数数组 nums 和一个整数 value 。
在一步操作中，你可以对 nums 中的任一元素加上或减去 value 。
nums = [1,2,3] 且 value = 2 ，你可以选择 nums[0] 减去 value ，得到 nums = [-1,2,3] 。数组的 MEX (minimum excluded) 是指其中数组中缺失的最小非负整数。
\n\n[-1,2,3] 的 MEX 是 0 ，而 [1,0,3] 的 MEX 是 2 。返回在执行上述操作 任意次 后，nums 的最大 MEX 。
\n\n
示例 1：
\n\n输入：nums = [1,-10,7,13,6,8], value = 5\n输出：4\n解释：执行下述操作可以得到这一结果：\n- nums[1] 加上 value 两次，nums = [1,0,7,13,6,8]\n- nums[2] 减去 value 一次，nums = [1,0,2,13,6,8]\n- nums[3] 减去 value 两次，nums = [1,0,2,3,6,8]\nnums 的 MEX 是 4 。可以证明 4 是可以取到的最大 MEX 。\n\n\n
示例 2：
\n\n输入：nums = [1,-10,7,13,6,8], value = 7\n输出：2\n解释：执行下述操作可以得到这一结果：\n- nums[2] 减去 value 一次，nums = [1,-10,0,13,6,8]\nnums 的 MEX 是 2 。可以证明 2 是可以取到的最大 MEX 。\n\n\n
\n\n
提示：
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