You are given the root of a binary tree that consists of exactly 3 nodes: the root, its left child, and its right child.
Return true if the value of the root is equal to the sum of the values of its two children, or false otherwise.
\n
Example 1:
\n![\"\"](\"https://assets.leetcode.com/uploads/2022/04/08/graph3drawio.png\")
\n\nInput: root = [10,4,6]\nOutput: true\nExplanation: The values of the root, its left child, and its right child are 10, 4, and 6, respectively.\n10 is equal to 4 + 6, so we return true.\n\n\n
Example 2:
\n![\"\"](\"https://assets.leetcode.com/uploads/2022/04/08/graph3drawio-1.png\")
\n\nInput: root = [5,3,1]\nOutput: false\nExplanation: The values of the root, its left child, and its right child are 5, 3, and 1, respectively.\n5 is not equal to 3 + 1, so we return false.\n\n\n
\n
Constraints:
\n\n-100 <= Node.val <= 100给你一个 二叉树 的根结点 root，该二叉树由恰好 3 个结点组成：根结点、左子结点和右子结点。
如果根结点值等于两个子结点值之和，返回 true ，否则返回 false 。
\n\n
示例 1：
\n\n\n输入：root = [10,4,6]\n输出：true\n解释：根结点、左子结点和右子结点的值分别是 10 、4 和 6 。\n由于 10 等于 4 + 6 ，因此返回 true 。\n\n\n
示例 2：
\n\n\n输入：root = [5,3,1]\n输出：false\n解释：根结点、左子结点和右子结点的值分别是 5 、3 和 1 。\n由于 5 不等于 3 + 1 ，因此返回 false 。\n\n\n
\n\n
提示：
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"exampleTestcases": "[10,4,6]\n[5,3,1]",
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