{ "data": { "question": { "questionId": "27", "questionFrontendId": "27", "categoryTitle": "Algorithms", "boundTopicId": 1347, "title": "Remove Element", "titleSlug": "remove-element", "content": "
Given an integer array nums
and an integer val
, remove all occurrences of val
in nums
in-place. The order of the elements may be changed. Then return the number of elements in nums
which are not equal to val
.
Consider the number of elements in nums
which are not equal to val
be k
, to get accepted, you need to do the following things:
nums
such that the first k
elements of nums
contain the elements which are not equal to val
. The remaining elements of nums
are not important as well as the size of nums
.k
.Custom Judge:
\n\nThe judge will test your solution with the following code:
\n\n\nint[] nums = [...]; // Input array\nint val = ...; // Value to remove\nint[] expectedNums = [...]; // The expected answer with correct length.\n // It is sorted with no values equaling val.\n\nint k = removeElement(nums, val); // Calls your implementation\n\nassert k == expectedNums.length;\nsort(nums, 0, k); // Sort the first k elements of nums\nfor (int i = 0; i < actualLength; i++) {\n assert nums[i] == expectedNums[i];\n}\n\n\n
If all assertions pass, then your solution will be accepted.
\n\n\n
Example 1:
\n\n\nInput: nums = [3,2,2,3], val = 3\nOutput: 2, nums = [2,2,_,_]\nExplanation: Your function should return k = 2, with the first two elements of nums being 2.\nIt does not matter what you leave beyond the returned k (hence they are underscores).\n\n\n
Example 2:
\n\n\nInput: nums = [0,1,2,2,3,0,4,2], val = 2\nOutput: 5, nums = [0,1,4,0,3,_,_,_]\nExplanation: Your function should return k = 5, with the first five elements of nums containing 0, 0, 1, 3, and 4.\nNote that the five elements can be returned in any order.\nIt does not matter what you leave beyond the returned k (hence they are underscores).\n\n\n
\n
Constraints:
\n\n0 <= nums.length <= 100
0 <= nums[i] <= 50
0 <= val <= 100
给你一个数组 nums
和一个值 val
,你需要 原地 移除所有数值等于 val
的元素。元素的顺序可能发生改变。然后返回 nums
中与 val
不同的元素的数量。
假设 nums
中不等于 val
的元素数量为 k
,要通过此题,您需要执行以下操作:
nums
数组,使 nums
的前 k
个元素包含不等于 val
的元素。nums
的其余元素和 nums
的大小并不重要。k
。用户评测:
\n\n评测机将使用以下代码测试您的解决方案:
\n\n\nint[] nums = [...]; // 输入数组\nint val = ...; // 要移除的值\nint[] expectedNums = [...]; // 长度正确的预期答案。\n // 它以不等于 val 的值排序。\n\nint k = removeElement(nums, val); // 调用你的实现\n\nassert k == expectedNums.length;\nsort(nums, 0, k); // 排序 nums 的前 k 个元素\nfor (int i = 0; i < actualLength; i++) {\n assert nums[i] == expectedNums[i];\n}\n\n
如果所有的断言都通过,你的解决方案将会 通过。
\n\n\n\n
示例 1:
\n\n\n输入:nums = [3,2,2,3], val = 3\n输出:2, nums = [2,2,_,_]\n解释:你的函数函数应该返回 k = 2, 并且 nums 中的前两个元素均为 2。\n你在返回的 k 个元素之外留下了什么并不重要(因此它们并不计入评测)。\n\n
示例 2:
\n\n\n输入:nums = [0,1,2,2,3,0,4,2], val = 2\n输出:5, nums = [0,1,4,0,3,_,_,_]\n解释:你的函数应该返回 k = 5,并且 nums 中的前五个元素为 0,0,1,3,4。\n注意这五个元素可以任意顺序返回。\n你在返回的 k 个元素之外留下了什么并不重要(因此它们并不计入评测)。\n\n\n
\n\n
提示:
\n\n0 <= nums.length <= 100
0 <= nums[i] <= 50
0 <= val <= 100
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