You are given a 0-indexed 2D integer array nums representing the coordinates of the cars parking on a number line. For any index i, nums[i] = [starti, endi] where starti is the starting point of the ith car and endi is the ending point of the ith car.
Return the number of integer points on the line that are covered with any part of a car.
\n\n\n
Example 1:
\n\n\nInput: nums = [[3,6],[1,5],[4,7]]\nOutput: 7\nExplanation: All the points from 1 to 7 intersect at least one car, therefore the answer would be 7.\n\n\n
Example 2:
\n\n\nInput: nums = [[1,3],[5,8]]\nOutput: 7\nExplanation: Points intersecting at least one car are 1, 2, 3, 5, 6, 7, 8. There are a total of 7 points, therefore the answer would be 7.\n\n\n
\n
Constraints:
\n\n1 <= nums.length <= 100nums[i].length == 21 <= starti <= endi <= 100给你一个下标从 0 开始的二维整数数组 nums 表示汽车停放在数轴上的坐标。对于任意下标 i，nums[i] = [starti, endi] ，其中 starti 是第 i 辆车的起点，endi 是第 i 辆车的终点。
返回数轴上被车 任意部分 覆盖的整数点的数目。
\n\n\n\n
示例 1：
\n\n\n输入：nums = [[3,6],[1,5],[4,7]]\n输出：7\n解释：从 1 到 7 的所有点都至少与一辆车相交，因此答案为 7 。\n\n\n
示例 2：
\n\n\n输入：nums = [[1,3],[5,8]]\n输出：7\n解释：1、2、3、5、6、7、8 共计 7 个点满足至少与一辆车相交，因此答案为 7 。\n\n\n
\n\n
提示：
\n\n1 <= nums.length <= 100nums[i].length == 21 <= starti <= endi <= 1000th index remove the overlapping parts and return the count of non-overlapping points."
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