You are given an integer array nums of length n.
In one operation, choose any subarray nums[l...r] (0 <= l <= r < n) and replace each element in that subarray with the bitwise AND of all elements.
Return the minimum number of operations required to make all elements of nums equal.
\n
Example 1:
\n\nInput: nums = [1,2]
\n\nOutput: 1
\n\nExplanation:
\n\nChoose nums[0...1]: (1 AND 2) = 0, so the array becomes [0, 0] and all elements are equal in 1 operation.
Example 2:
\n\nInput: nums = [5,5,5]
\n\nOutput: 0
\n\nExplanation:
\n\nnums is [5, 5, 5] which already has all elements equal, so 0 operations are required.
\n
Constraints:
\n\n1 <= n == nums.length <= 1001 <= nums[i] <= 105给你一个长度为 n 的整数数组 nums。
在一次操作中，可以选择任意子数组 nums[l...r] （0 <= l <= r < n），并将该子数组中的每个元素 替换 为所有元素的 按位与（bitwise AND）结果。
返回使数组 nums 中所有元素相等所需的最小操作次数。
子数组 是数组中连续的、非空的元素序列。
\n\n\n\n
示例 1：
\n\n输入： nums = [1,2]
\n\n输出： 1
\n\n解释：
\n\n选择 nums[0...1]：(1 AND 2) = 0，因此数组变为 [0, 0]，所有元素在一次操作后相等。
示例 2：
\n\n输入： nums = [5,5,5]
\n\n输出： 0
\n\n解释：
\n\nnums 本身是 [5, 5, 5]，所有元素已经相等，因此不需要任何操作。
\n\n
提示：
\n\n1 <= n == nums.length <= 1001 <= nums[i] <= 105nums are already equal, how many operations are needed?",
"The answer is either 0 or 1.",
"The answer is 0 if all values in the array are initially equal, and 1 otherwise, since you can apply the AND operation on the whole array in one step."
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