{ "data": { "question": { "questionId": "1393", "questionFrontendId": "2218", "categoryTitle": "Algorithms", "boundTopicId": 1366027, "title": "Maximum Value of K Coins From Piles", "titleSlug": "maximum-value-of-k-coins-from-piles", "content": "

There are n piles of coins on a table. Each pile consists of a positive number of coins of assorted denominations.

\n\n

In one move, you can choose any coin on top of any pile, remove it, and add it to your wallet.

\n\n

Given a list piles, where piles[i] is a list of integers denoting the composition of the ith pile from top to bottom, and a positive integer k, return the maximum total value of coins you can have in your wallet if you choose exactly k coins optimally.

\n\n

 

\n

Example 1:

\n\"\"\n
\nInput: piles = [[1,100,3],[7,8,9]], k = 2\nOutput: 101\nExplanation:\nThe above diagram shows the different ways we can choose k coins.\nThe maximum total we can obtain is 101.\n
\n\n

Example 2:

\n\n
\nInput: piles = [[100],[100],[100],[100],[100],[100],[1,1,1,1,1,1,700]], k = 7\nOutput: 706\nExplanation:\nThe maximum total can be obtained if we choose all coins from the last pile.\n
\n\n

 

\n

Constraints:

\n\n\n", "translatedTitle": "从栈中取出 K 个硬币的最大面值和", "translatedContent": "

一张桌子上总共有 n 个硬币  。每个栈有 正整数 个带面值的硬币。

\n\n

每一次操作中,你可以从任意一个栈的 顶部 取出 1 个硬币,从栈中移除它,并放入你的钱包里。

\n\n

给你一个列表 piles ,其中 piles[i] 是一个整数数组,分别表示第 i 个栈里 从顶到底 的硬币面值。同时给你一个正整数 k ,请你返回在 恰好 进行 k 次操作的前提下,你钱包里硬币面值之和 最大为多少 。

\n\n

 

\n\n

示例 1:

\n\n

\"\"

\n\n
\n输入:piles = [[1,100,3],[7,8,9]], k = 2\n输出:101\n解释:\n上图展示了几种选择 k 个硬币的不同方法。\n我们可以得到的最大面值为 101 。\n
\n\n

示例 2:

\n\n
\n输入:piles = [[100],[100],[100],[100],[100],[100],[1,1,1,1,1,1,700]], k = 7\n输出:706\n解释:\n如果我们所有硬币都从最后一个栈中取,可以得到最大面值和。\n
\n\n

 

\n\n

提示:

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exact-integer?)\n )", "__typename": "CodeSnippetNode" }, { "lang": "Erlang", "langSlug": "erlang", "code": "-spec max_value_of_coins(Piles :: [[integer()]], K :: integer()) -> integer().\nmax_value_of_coins(Piles, K) ->\n .", "__typename": "CodeSnippetNode" }, { "lang": "Elixir", "langSlug": "elixir", "code": "defmodule Solution do\n @spec max_value_of_coins(piles :: [[integer]], k :: integer) :: integer\n def max_value_of_coins(piles, k) do\n \n end\nend", "__typename": "CodeSnippetNode" }, { "lang": "Cangjie", "langSlug": "cangjie", "code": "class Solution {\n func maxValueOfCoins(piles: ArrayList>, k: Int64): Int64 {\n\n }\n}", "__typename": "CodeSnippetNode" } ], "stats": "{\"totalAccepted\": \"10.3K\", \"totalSubmission\": \"17.4K\", \"totalAcceptedRaw\": 10269, \"totalSubmissionRaw\": 17447, \"acRate\": \"58.9%\"}", "hints": [ "For each pile i, what will be the total value of coins we can collect if we choose the first j coins?", "How can we use dynamic programming to combine the results from different piles to find the most optimal answer?" ], "solution": null, "status": null, "sampleTestCase": "[[1,100,3],[7,8,9]]\n2", "metaData": "{\n \"name\": \"maxValueOfCoins\",\n \"params\": [\n {\n \"name\": \"piles\",\n \"type\": \"list>\"\n },\n {\n \"type\": \"integer\",\n \"name\": \"k\"\n }\n ],\n \"return\": {\n \"type\": \"integer\"\n }\n}", "judgerAvailable": true, "judgeType": "large", "mysqlSchemas": [], "enableRunCode": true, "envInfo": "{\"cpp\":[\"C++\",\"

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