You are given an integer array nums with a length divisible by 3.
You want to make the array empty in steps. In each step, you can select any three elements from the array, compute their median, and remove the selected elements from the array.
\n\nThe median of an odd-length sequence is defined as the middle element of the sequence when it is sorted in non-decreasing order.
\n\nReturn the maximum possible sum of the medians computed from the selected elements.
\n\n\n
Example 1:
\n\nInput: nums = [2,1,3,2,1,3]
\n\nOutput: 5
\n\nExplanation:
\n\nnums becomes [2, 1, 2].nums becomes empty.Hence, the sum of the medians is 3 + 2 = 5.
Example 2:
\n\nInput: nums = [1,1,10,10,10,10]
\n\nOutput: 20
\n\nExplanation:
\n\nnums becomes [1, 10, 10].nums becomes empty.Hence, the sum of the medians is 10 + 10 = 20.
\n
Constraints:
\n\n1 <= nums.length <= 5 * 105nums.length % 3 == 01 <= nums[i] <= 109给你一个整数数组 nums，其长度可以被 3 整除。
你需要通过多次操作将数组清空。在每一步操作中，你可以从数组中选择任意三个元素，计算它们的 中位数 ，并将这三个元素从数组中移除。
\n\n奇数长度数组的 中位数 定义为数组按非递减顺序排序后位于中间的元素。
\n\n返回通过所有操作得到的 中位数之和的最大值 。
\n\n\n\n
示例 1：
\n\n输入： nums = [2,1,3,2,1,3]
\n\n输出： 5
\n\n解释：
\n\nnums 变为 [2, 1, 2]。nums 变为空数组。因此，中位数之和为 3 + 2 = 5。
示例 2：
\n\n输入： nums = [1,1,10,10,10,10]
\n\n输出： 20
\n\n解释：
\n\nnums 变为 [1, 10, 10]。nums 变为空数组。因此，中位数之和为 10 + 10 = 20。
\n\n
提示：
\n\n1 <= nums.length <= 5 * 105nums.length % 3 == 01 <= nums[i] <= 109nums.",
"Repeatedly pick the largest 2 values and the minimum value."
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